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professor190 [17]
3 years ago
6

Can someone please tell me how to factorise 5x squared takeaway 80y squared

Mathematics
1 answer:
GuDViN [60]3 years ago
5 0
80y² - 5x²

Factorise

5(16y²-x²)

hope this helps

divide out any similar things, in this case, it is 5

put it outside the parenthesis, and leave the leftover inside the parenthesis

hope this helps
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Please help me answer this question
Jlenok [28]

Answer:c

Step-by-step explanation:

4/3 times pi times 7 cubed

5 0
3 years ago
Rachel has a box in the shape of a prism with a square base. The capacity of the box is 150 cubic inches. The height of the box
hjlf
V = s²h 

<span>150 = s²h </span>
<span>150 = s²(3/2)s </span>
<span>(2/3)150 = s³ </span>
<span>100 = s³ </span>
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6 0
4 years ago
1 Select the correct answer. Multiply the binomials: (3x + 4)(5x - 2) A.15x2 + 20x-8b. 15x2 + 14x-8 c. 15x2- 14x-8 D. 15x2+ 14x8
leonid [27]

Multiply the binomials:



(3x + 4)(5x - 2)

\begin{gathered} =3x(5x\text{ - 2) + 4(5x - 2)} \\ =15x^2\text{ - 6x + 20x - 8} \\ =15x^2\text{ + 14x - 8} \end{gathered}

Final answer

Option B is the final answer

3 0
1 year ago
What is the simplified base for the function f(x) = 2?<br><br> 2<br> 3<br> 9<br> 18
Nina [5.8K]
This is 9 I would have to say.
5 0
3 years ago
Read 2 more answers
I have the answer, 2-(3/x+2)
Marat540 [252]

Start with the answer format we want, and work your way toward forming a single fraction like so

a + \frac{b}{x+2}\\\\a*1+\frac{b}{x+2}\\\\a*\frac{x+2}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)+b}{x+2}\\\\\frac{ax+2a+b}{x+2}\\\\\frac{ax+(2a+b)}{x+2}\\\\

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.

Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.

So, 4+b = 1 leads to b = -3

Therefore, a = 2 and b = -3

------------------------------------------------

An alternative route:

\frac{2x+1}{x+2}\\\\\frac{2x+1+0}{x+2}\\\\\frac{2x+1+4-4}{x+2}\\\\\frac{(2x+4)+1-4}{x+2}\\\\\frac{2(x+2)-3}{x+2}\\\\\frac{2(x+2)}{x+2}+\frac{-3}{x+2}\\\\2-\frac{3}{x+2}\\\\

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.

------------------------------------------------

Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.

3 0
3 years ago
Read 2 more answers
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