Answer:
Grayson has to walk 1.7 miles across the field.
Step-by-step explanation:
We have drawn the diagram for your reference.
Given:
Grayson usually walks 1.5 miles west on the side walks
According to Diagram we can say;
CA = 1.5 miles
Also Given:
Grayson also walks 0.8 miles north on the sidewalks
So According to Diagram we can say;
BA =0.8 miles
Now we need to find number of miles Grayson have to walk across the field.
According to diagram we can say;
We have to find CA.
Assuming the diagram to be right angled triangle.
We can find CA using Pythagoras theorem.
Substituting the given values we get;
Taking square root on both side we get;
Hence Grayson has to walk 1.7 miles across the field.
(2,13),(5,22)
slope = (22 - 13) / (5 - 2) = 9/3 = 3
y = mx + b
slope(m) = 3
use either of ur points...(2,13)...x = 2 and y = 13
now sub and find b, the y int
13 = 3(2) + b
13 = 6 + b
13 - 6 = b
7 = b
so ur equation is : y = 3x + 7 <===
Answer:
51
Step-by-step explanation:
75 - 67 = 8
67 - 59 = 8
The difference between terms is 8
To find the next term take 59 -8
59-8 = 51
Check 51 -8 = 43 so we are correct
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
π
Step-by-step explanation:
s = (∅/360) * (2πr)
s = (60/360) * (2π*3)
s = (1/6) * (6π)
s = π
