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Verdich [7]
3 years ago
7

PLEASE PLEASE PLEASE HELP ME!

Mathematics
2 answers:
VladimirAG [237]3 years ago
5 0

Answer: 50 Minutes = 309 gal

Step-by-step explanation: Every 10 minutes the amount of water goes up by 18, so after 50 minutes the water would be equivalent to 309 gallons.

raketka [301]3 years ago
4 0

Answer:

y=1.8x+219

309 gallons

Step-by-step explanation:

So to find the linear equation, we can use the data from the table.

First, use the data from the table to find the slope. Pick any two points. I'm going to use (10,237) and (20,255).

Let (10,237) be x₁ and y₁ and let (20,255) be x₂ and y₂.

The formula for slope is given by:

m=\frac{y_2-y_1}{x_2-x_1}

Substitute:

m=\frac{255-237}{20-10}

Simplify:

m=18/10=1.8

Thus, the slope is 1.8. This means that 1.8 gallons of water flow into the tank every minute.

Now, let's find the slope-intercept. To do this, we can use the point-slope form. The point-slope form is:

y-y_1=m(x-x_1)

Let's use (10,237) for consistency. Plug in 237 for y₁  and 10 for x₁. Also use 1.8 for m. Thus:

y-237=1.8(x-10)

Distribute:

y-237=1.8x-18

Add 237 to both sides:

y=1.8x+219

What this means is that there is initially 219 gallons of water in the tank already. Every minute, 1.8 gallons is added further.

And that's our linear equation :)

So, to find the amount of gallons after 50 minutes, plug in 50 for x and solve:

y=1.8(50)+219\\y=90+219=309

After 50 minutes, there will be 309 gallons of water.

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Please answer my question
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What is the best estimate for the number of people in line at 7.A.M
Keith_Richards [23]

We have been given the equation

y=-5.131x^2+31.821x-3.333

It represents the number of people standing to catch a commuter train x hours after 5 A.M.

Now, in order to find the number of people in line at 7 a.m. , we need to substitute x= 2 in the above equation.

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D id the correct option.

5 0
3 years ago
An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t
Arte-miy333 [17]

Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

3 0
3 years ago
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