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3 years ago

How is 0.246¯¯¯¯ written as a fraction in simplest form?

Mathematics

2 answers:

xeze [42]3 years ago

6 0

123/500

is the answer......................................

VashaNatasha [74]3 years ago

3 0

246/1000 simplified would be 123/500.

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The area of a triangle is found by multiplying half of the measure of its base by its height. The area of the following right tr

GarryVolchara [31]

Answer:

$\sf Area\:of\:a\:triangle=\dfrac12 \times base \times height$

Given:

area = 18 cm²
base = 6 cm
height = (h + 1) cm

Substitute the given values into the equation and solve for h:

$\sf \implies 18 = \sf \dfrac12 \times 6 \times (h+1)$

$\sf \implies 18 = \sf \dfrac62 (h+1)$

$\sf \implies 18 =3(h+1)$

expand using distributive property of addition $a(b+c)=ab+ac$ :

$\sf \implies 18=3h+3$

subtract 3 from both sides:

$\sf \implies 3h=15$

divide both sides by 3:

$\sf \implies h=5$

<u>To verify</u>:

Half of the base is 3 cm.

If h=5, then the height of the triangle is 6 cm.

Multiplying 3 by 6 is 18.

This matches the given area, so we can verify that h = 5.

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1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio

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Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image $(x,y)\rightarrow Image(kx,ky)$

where $k$ represents the scalar factor.

We can find value of $k$ for the given co-ordinates by finding the ratio of $x$ or $y$ co-ordinates of the image and pre-image.

$k=\frac{Image}{Pre-Image}$

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of $k=\frac{-60}{-12}=5$

or $k=\frac{15}{3}=5$

As we get $k=5$ for both ratios i.e of $x$ and $y$ co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

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