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Lera25 [3.4K]
3 years ago
14

Which expression is equivalent to (cd)^5? O c^5 +d^5 O c^5/d^5 O c^5d^5 O c^5-d^5

Mathematics
1 answer:
Elenna [48]3 years ago
3 0
The third one

c^5•d^5

Hope this helps!
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What are the coordinates of point P on the coordinate grid below?
Leona [35]
The coordinates are (-3/8, 5/8), work is shown in the picture attached
5 0
3 years ago
Solve each system of equations <br> 2x- 5y = 7<br> 3x - y = -9
Darina [25.2K]

Answer:

x = -4; y = -3

Step-by-step explanation:

2x - 5y = 7

3x - y = -9

Rewrite top equation. Multiply both sides of bottom equation by -5. Add equations. This eliminates y, and we solve for x.

         2x - 5y = 7

(+)   -15x + 5y = 45

----------------------------

      -13x         = 52

Divide both sides by -13.

x = -4

Substitute -4 for x in the first original equation and solve for y.

2x - 5y = 7

2(-4) - 5y = 7

-8 - 5y = 7

-5y = 15

y = -3

Answer: x = -4; y = -3

-5 =

8 0
3 years ago
What is 1 1/5 subtracted by 3 1/10<br>whoever gets it right I will choose as the brainliest
pickupchik [31]

Answer:

6/5÷31/10=12/31

Step-by-step explanation:

6/5÷31/10=?Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

6/5×10/31=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

6×10 5×31=60/155

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 60 and 155 using

GCF(60,155) = 5

60÷51   55÷5=12/31

Therefore:

65÷3110=12/31

7 0
3 years ago
Plz help 4th grade review
Soloha48 [4]
C:5

just divide 445 by 89 and you get 5

5 0
3 years ago
Read 2 more answers
Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles
Bas_tet [7]

Answer:

a) We reject H₀     We find difference between the mean of the two groups

b) we accept H₀ : There is no statistical difference  ( in the scale of pain) when the difference in samples means is 1

Step-by-step explanation:

Group 1: Only with educational material

Sample size     n₁  =  42

Sample mean   x₁  =  3,2

Sample standard deviation  s₁  =  2,3

Group 2: With exercises with the treatment of individuals

Sample size    n₂   =  42

Sample mean    x₂  = 5,2  

Sample standard deviation   s₂  = 2,3

Test Hypothesis

Null Hypothesis                     H₀           x₂  -  x₁  = 0  or    x₁  =  x₂

Alternative Hypothesis         Hₐ           x₂  -  x ₁ > 0  or    x₂  >  x₁

Significance level  α  = 0,01

Sample sizes are n₁  =  n₂  >  30

We use z-test

for α  = 0,01     z(c)  ≈  2,32

To calculate z(s)

z(s)  =  (  x₂  -  x₁ ) / √ (2,3)²/42  + (2,3)²/42

z(s)  = ( 5,2  -  3,2 )/ √0,2519

z(s)  =  2 / 0,5

z(s) = 4

Comparing  z(s)  and z(c)

z(s) > z(c)

z(s) is in the rejection region. We reject H₀ the true average pain level for the control condition exceeds that for the treatment condition.

b) Does the true average pain level for the control condition exceed that for the treatment condition by more than 1.

In this case

z( s) =  x₂ - x₁ / 0,5

z(s) =  1 /0,5

z(s) = 2

Comparing z(s) and z(c)  now

z(s) < z(c)        2 < 2,32

And z(s) is in the acceptance region ( for the same significance level) and we should accept H₀  equivalent to say that the two groups statistical have the same mean

5 0
3 years ago
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