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madam [21]
4 years ago
8

The Mississippi River is about 4,000 kilometers long. An M&M is about 1 centimeter long. There are 100 centimeters in a mete

r, and 1,000 meters in a kilometer. Estimate how many M&Ms it would take to measure the length of the Mississippi River
Mathematics
1 answer:
harkovskaia [24]4 years ago
4 0
To be able to determine the number of M&Ms that are needed in order to measure the length of Mississippi River, we convert the units to a common one. For this purpose, we convert kilometers to centimeter such that,
 
Length of Mississippi River = (4000 km)(1000 m/1 km)(100 cm/1 m)
                       = 400,000,000 cm

Since there are 400,000,000 cm in the entire length of the river, the answer would also be 400,000,000. 
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The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
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Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

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Answer: x=-7

Step-by-step explanation: hope this help :)

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