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Svetradugi [14.3K]

3 years ago

14

The Glen Wastewater Treatment plant is going to increase in capacity from 750,000 gallons of wastewater treated per day to 3 mil

lion. What percent increase is this?

2 answers:

satela [25.4K]3 years ago

8 0

I got that it's a 300% increase. Because it's increased by 2250000, then you find what percent of 750000 that is.

saveliy_v [14]3 years ago

5 0

It would be a 400% increase

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(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

$E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))$

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$= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

Now $P(X(s) \leq 0) = P(X(s) = 0)$

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Now; $P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)$

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of $W_2$ given that X(t)=5 is:

$f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)$

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With intervals, we do not know the exact data points. They just fall into a range.

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