The area of the triangle ABC is 207.5 square units.
Explanation:
The measurements of the sides of the triangle are 
, 
and 
We need to determine the area of the triangle ABC.
<u>Area of the triangle:</u>
The area of the triangle can be determined using the formula,
where 
, 
and
Substituting these values in the above formula, we get,
Simplifying the values, we get,
Rounding off to the nearest tenth, we get,
Thus, the area of the triangle ABC is 207.5 square units.
Answer:
the horizontal position for the left edge of the image is -4.46 cm.
Step-by-step explanation:
The horizontal midpoint of the page is:
21.59 / 2 = 10.79 cm
The horizontal midpoint of the image is given as:
30.51 / 2 = 15.25 cm
These midpoints must be on the same point in the axis.
By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.
The distance that goes beyond this leftmost edge is computed as;
This is on the negative side on the axis.
Thus the horizontal position for the left edge of the image is -4.46 cm.
D. Is the ans
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Answer:
Midpoint (-2,4)
distance nearest tenth = 8.9
The approximate distance = 9
Step-by-step explanation:
Formulas
PQ midpoint = (x2 + x1)/2, (y2 + y1)/2
distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Givens
x2 = -4
x1 = 0
y2 = 1
y1 = 7
Solution
M(PQ) = (-4+0)/2, (1 + 7)/2
M(PQ) = -2, 4
The midpoint is -2,4
The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )
The distance = sqrt(16 + 64)
The distance = sqrt(80)
The distance = 4√5 exactly
The distance = 8.94
The distance = 8.9 To the nearest tenth
Question 2
The distance is rounded to the nearest whole number which is 9.
