The values of a and b will be -2 and 22 while the other factor in the function is x - 3/2.
<h3>How to illustrate the function?</h3>
The function is given as:
f(x) = ax³ - x² + bx - 24.
Since (x - 2) and (x - 4) are the factors, they will give functions of 8a + 2b = 28 and -16a - b = 10.
This will be solved by elimination method and the values of a and b will be -2 and 22.
Therefore, f(x) = -2x³ - x² + 22x - 24
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I encountered this problem before but it had an accompanying image and list of answer choices.
I'll attach the image and include the list of options.
Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
<span>D) Distance Formula and Pythagorean Theorem
</span>
My answer is: D.) Distance formula and Pythagorean Theorem.
When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse.
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.
The dimensions such as length is 18 and width is 16 or length is 32 and width is 9 will produce an enclosed area of 288ft.
<h3>What is the dimension of length and width?</h3>
We know that,
P = l + 2w
50 = l + 2w
50 - 2w = l
A = l x w
288 = (50 - 2w)w
288 = 50w -2w²
2w² - 50w + 288
By dividing throughout by 2
w² - 25w + 144
This is in quadratic equation form.
By applying quadratic formula,
w = (-(-25) ±
) / 2
w = (-(-25) ± 7)/2
w1 = (-(-25) + 7)/2
w1 = (25 + 7) / 2
w1 = 16
w2 = (-(-25) - 7)/2
w2 = (25 - 7) / 2
w2 = 9
By substituting the values in eq1,
A = l x w
if w = 16
288 = l x 16
l = 288/16
l = 18
if w = 9
288 = l x 9
l = 288/9
l = 32
The dimensions will be length is 18 and width is 16 or length is 32 and width is 9.
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Jk= 18
Kl= 10
3x - 2 = 28
+2. +2
3x / 3 and 30 / 3 = 10
28-10 = 18