Answer:
Step-by-step explanation:
A(-6,2) =>A'(-5, -1)
B(-5,4) =>B'( -4,1)
C(-2,4)=> C'(-1,1)
D( 1,2) => D'(2,-1)
we move all these points to (x+1, y-3)
Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
Answer:
- boat: 6 mph
- current: 2 mph
Step-by-step explanation:
The relationship between time, speed, and distance is ...
speed = distance/time
For boat speed b and current speed c, the speed downstream is ...
b +c = (16 mi)/(2 h) = 8 mi/h
The speed upstream is ...
b -c = (16 mi)/(4 h) = 4 mi/h
Adding the two equations eliminates the c term:
2b = 12 mi/h
b = 6 mi/h . . . . . divide by 2
Solving the second equation for c, we get ...
c = b -4 mi/h = 6 mi/h -4 mi/h = 2 mi/h
The speed of the boat in still water is 6 mi/h; the current is 2 mi/h.
Answer:
(a) 144
(b) 117
(c) 360
(d) 588
(e) 5472
Step-by-step explanation:
To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.
2.
(a)



(b)



(c)



(d)



(e)



Step-by-step explanation:
Marla drove 567
Gudio drove 560
The trip was 679