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arsen [322]
3 years ago
6

Find the value of x for the figure below

Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer:

84

Step-by-step explanation:

because the top and bottom lines are parallel, we can conclude that the 2 triangles (top and bottom) are similar triangles. This means the sides lengths  of smaller triangle is proportional to the respective sides on the larger triangle. With this, we can form the following equation:

x/48 = 21/12  (multiply both sides by 48)

x = (21/12)· 48

x = 21 ·4

x = 84

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Sam intends to roll a six sided cube 100 times. What is the probability model he can use to predict whether or not each roll wil
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Each trial is independent.

In the given experiment of 100 trials, the binomial probability model can be used to predict the number of occurrence of non-prime numbers (X). The probability mass function is

P(X=x)=C(100,x)p^x(1-p)^{100-x},x=0,1,2,3,...,100. Since p=0.5,1-p=0.5

P(X=x)=C(100,x)0.5^x(0.5)^{100-x},x=0,1,2,3,...,100 \\ P(X=x)=C(100,x)(0.5)^{100},x=0,1,2,3,...,100

8 0
3 years ago
Read 2 more answers
8. A rain barrel collected 75 gallons of water. Water leaked
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Answer:

30 days (do correct me if I'm wrong haha)

Step-by-step explanation:

5 gallons = 2 days

75 gallons = 30 days

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7 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
Shawn incorrectly graphed the inequality -x-2y≥8 as shown below Explain shawn mistake ​rotate phone if u need to
Aleks04 [339]

Answer:

He failed to flip the inequality

y ≤-1/2x-4

Step-by-step explanation:

-x-2y ≥8

Add x to each side

-x+x-2y ≥x+8

-2y ≥x+8

Divide by -2.  Remember to flip the inequality

-2y/-2 ≤-1/2 x +8/-2

y ≤-1/2x-4

Shawn shaded the wrong side of the line.

Y is less than or equal to .  He failed to flip the inequality

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