It looks like the scale is balanced so that means you can set one side equal to the other which leaves you with the equation x+(-10)=-16
To get x by itself add x to each side to get x=-6
X=-6 is your answer
Answer: It would be approximately 2000 ft.
Step-by-step explanation:
Answer:
Part A) Option A. QR= 3 cm
Part B) Option B. SV=6.5 cm
Step-by-step explanation:
step 1
<u>Find the length of segment QR</u>
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
so
In this problem Triangle QRW and Triangle QSV are similar by AA Similarity Theorem
so
![\frac{QR}{QS}=\frac{QW}{QV}](https://tex.z-dn.net/?f=%5Cfrac%7BQR%7D%7BQS%7D%3D%5Cfrac%7BQW%7D%7BQV%7D)
we have
---> because S is the midpoint QT (QS=TS)
--->because V is the midpoint QU (QW+WV=VU)
--->because V is the midpoint QU (QV=VU)
substitute the given values
![\frac{QR}{9}=\frac{2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7BQR%7D%7B9%7D%3D%5Cfrac%7B2%7D%7B6%7D)
solve for QR
![QR=9(2)/6=3\ cm](https://tex.z-dn.net/?f=QR%3D9%282%29%2F6%3D3%5C%20cm)
step 2
Find the length side SV
we know that
The <u><em>Mid-segment Theorem</em></u> states that the mid-segment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this mid-segment is half the length of the third side
so
In this problem
S is the mid-point side QT and V is the mid-point side QU
therefore
SV is parallel to TU
and
![SV=(1/2)TU](https://tex.z-dn.net/?f=SV%3D%281%2F2%29TU)
so
![SV=(1/2)13=6.5\ cm](https://tex.z-dn.net/?f=SV%3D%281%2F2%2913%3D6.5%5C%20cm)
![\lambda = _0^{200}\sum (i)^f = 1+50(i-1-i+1) = 1 + 0i](https://tex.z-dn.net/?f=%5Clambda%20%3D%20_0%5E%7B200%7D%5Csum%20%28i%29%5Ef%20%3D%201%2B50%28i-1-i%2B1%29%20%3D%201%20%2B%200i)
From this we know that
![\lambda](https://tex.z-dn.net/?f=%5Clambda)
lies on the x-axis.
If z = 0, then k =
![\lambda](https://tex.z-dn.net/?f=%5Clambda)
and point lies on curve L.
I believe the answer is C. It definitely not A or B.