If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?
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оооо
1 answer:
Answer:
(f+g) (x) =0 for x=-2
Step-by-step explanation:
f(x) = x^2 – 2x, g(x) = 6x + 4,
(f+g) (x) =f(x) +g(x) =
(x^2 – 2x) + (6x + 4) =
x^2 – 2x+ 6x + 4=
x^2 +4x+4
(f+g)(x) =x^2 +4x+4=0 (quvadratic equation)
x^2 +4x+4=x^2 +2x*2+2^2=(x+2)^2
then
(x+2)^2 =0
x+2=0
x=-2
(f+g) (x) =0 for x=-2
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