Question

PLEASE HELP me solve algebraically. J) 4(1-2j) = 7(2j + 10) K) 4/3h=12 L) n/5= 2 + n/3 M) d/4 - 2/3 = 2 N= 7= -2 (-3 - x)

Answer 1

Answer:

J ) j = - 3,

K ) h = 9,

M ) d = - 24,

N ) x = 1 / 2

Step-by-step explanation:

J )

$4(1-2j) = 7(2j + 10),\\4-8j=14j+70,\\-8j=14j+66,\\\\-22j=66,\\j = - 3,\\\\Solution, j = - 3$

I applied the distributive property, resulting in the second step. Afterwards I subtracted 4 from either side of the equation, received - 22j = 66 after combining like terms, and divided - 22 on either side to get j = -3.

K )

$4 / 3h = 12,\\4h = 36,\\h = 36 / 4 = 9\\\\Solution, h = 9$

Multiplying each end of the equation by 3 resulted in the simplified expression 4h = 36. Dividing either side by 4, I got h = 9.

M )

$d / 4 - d / 3 = 2,\\3d - 4d = 24,\\- d = 24,\\\\Solution, d = - 24$

Taking the LCM of 4 and 3, I got 12, multiplying either side by 12 / 12. Combining like terms and dividing - 1 on either side of the equation - d = 24, I received d = - 24.

N )

$7 = - 2 * ( - 3 - x ),\\- 3 - x = - 7 / 2,\\- x = - 1 / 2,\\\\Solution, x = 1 / 2$

After dividing the first equation by - 2 on each end, I received a simplified equation that, by adding 3 on it's part, got x to be = 1 / 2