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3 years ago

Please help me, thank you.

Mathematics

1 answer:

jeka943 years ago

6 0

I think its C............. :) I'm sorry if I got it wrong

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Explain the difference between accuracy and precision

nata0808 [166]

Precision is more like consistency. Take a rifle range for example. Sure, all the shots may be off centered, but if they're tightly grouped together, it shows that the shooter had precision in their shooting. Accuracy is how close to spot on the attempts or shots generally are. They would end up more towards the center, but a little more spread out.

3 0

4 years ago

Read 2 more answers

The right rectangular prism is made up of 48 cubes. Each cube has an edge length of inch. What is the volume of this prism?

Gnesinka [82]

Given:

The right rectangular prism is made up of 48 cubes.
Each cube has an edge length of 1/4 inch.

$~$

To Find:

What is the volume of this prism?

$~$

Solution:

$~$

Using formula: 

$~$

$\sf \pmb {Volume \: of \: cube = {(side)}^{3} }$

$~$

Substituting values in the formula:

$~$

$\sf \longrightarrow \dfrac{1}{4} \times \dfrac{1}{4} \times \dfrac{1}{4}$

$\sf \longrightarrow \dfrac{1}{64} \: {inch}^{3}$

$~$

Now,

Volume of 48 such cubes = Volume of 1 cube × 48 cubes

$~$

$\sf \longrightarrow \dfrac{1}{64} \times 48$

$\sf \longrightarrow \dfrac{48}{64}$

$\sf \longrightarrow \dfrac{3}{4} \: {inch}^{3}$

$~$

Hence,

Volume of prism is 3/4 inch^3

7 0

3 years ago

What is the area of the sector with a central angle of 49° and a radius of 11 cm? Use 3.14 for pi and round your final answer to

olga_2 [115]

Answer:

$\boxed{\text{51.71 cm}^{2}}$

Step-by-step explanation:

If the angle θ is in radians, the formula for the area (A) of a sector of a circle is

A = ½r²θ

If θ is in degrees

$A = \dfrac{1}{2}r^{2}\theta \times \dfrac{\pi \text{ rad}}{180^{\circ}}= \pi r^{2}\times\dfrac{\theta }{360}$

Data:

θ = 49°

r = 11 cm

Calculation:

$\begin{array}{rcl}A& = &3.14\times 11^{2}\times\dfrac{49}{360}\\\\ & = &3.14 \times 121 \times 0.1361\\ & = & \mathbf{51.71}\\\end{array}\\\text{The area of the sector is }\boxed{\textbf{51.71 cm}^{2}}$