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Sunny_sXe [5.5K]
3 years ago
10

Calculate the slope of a line that passes through the following two points.

Mathematics
2 answers:
____ [38]3 years ago
6 0

Answer:

Yo, the slope of the line is 6 yo!

Step-by-step explanation:

You see, to find the slope of 2 points, Here's what ya do little fella: Pick any y-coordinate point(-2) or (-8). When you do, subtract -2 and -8 so in this case,      -y - (-x) = -y + x. So, when done correctly, you get 6 because -2 - (-8) is equal to -2 + 8. Ya go to the x-coordinate. If you subtracted -8 from -2, you have to subtract 4 from 5. If you also subtracted -2 from 8, you have to subtract 5 from 4. So, it has to be in order. 5 - 4 = 1. So then, you divide your answer 6/1 = 6. So 6 is the slope people. NA YOU PEOPLE EHN, YA BETTER GO AND START LEARNING ALGEBRA.

AlekseyPX3 years ago
3 0

Answer:

the slope is 6 (6/1)

Step-by-step explanation:

Use the slope formula: y2-y1/x2-x1 ( i did the one that was further to the right ats the second pair rather than the order that you put it in)

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A private ship carries two types of cargo: large crates and extra-large crates. Each type of crate weighs a specific amount.
Arisa [49]

Answer:

G. 32

Step-by-step explanation:

32 x 335 = 10720

16,100 - 10720 = 5380/190 = 28.3157894737

275 x 32 = 8800

18,800 - 8800 = 10,000/400 = 25 (This is the closer).

30 x 335 = 10,050

16,100 - 10,050 = 6050/190  = 31.8421052632

30 x 275 = 8250

18,800 - 8250 = 10550/400 = 26.375 (Same reason why it does't work)

25 x 335 = 8375

16,100 - 8375 = 7725/190 = 40.6578947368

25 x 275 = 6875

18,800 - 6875 = 11925/400 = 29.8125

24 x 335 = 8040

16,100 - 8040 = 8060/190 = 42.4210526316

24 x 275 = 6600

18,800 - 6600 = 12200/400 = 30.5

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Calculate the product: 4/5 x 55
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4/5 x55
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By inference  X //  Z


The third option.
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Answer:

The real numbers are any number that corresponds to a point on the line Real and can be classified into numbers natural, whole, rational and irrational. In other words, any real number is between minus infinity and plus infinity and we can represent it on the real line .

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