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2 years ago

Please help me with this

Mathematics

1 answer:

Alexandra [31]2 years ago

5 0

Answer:

Step-by-step explanation:

Subtract 8 from 11.

3^3−2⋅6

Raise 3 to the power of 3.

27−2⋅6

Multiply −2 by 6

27−12

Subtract 12 from 27

hope this helps plz mark brainliest

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4 years ago

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Y_Kistochka [10]

The correct answer is option B which is $SinA = \dfrac{4}{5}$ , $tanA = \dfrac{4}{3}$ , $SecA=\dfrac{5}{3}$ ,

$CosA=\dfrac{3}{5}$ , $CotA=\dfrac{3}{4}$ and $CscA=\dfrac{5}{4}$ .

<h3>What is trigonometry?</h3>

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

From the figure we can see that two sides are Ab = 15 cm and BC = 12 cm third side will be calculated by pythagorean theorem.

AC² = AB² - BC²

AC² = 15² - 12²

AC² = 81

AC = √81

AC = 9 cm

Now all the trigonometry identities are:-

$SinA =\dfrac{BC}{AB}=\dfrac{12}{15}= \dfrac{4}{5}$ ,

$tanA =\dfrac{BC}{AC}=\dfrac{12}{9}= \dfrac{4}{3}$ ,

$SecA=\dfrac{AB}{AC}=\dfrac{15}{9}= \dfrac{5}{3}$ ,

$CosA=\dfrac{AC}{AB}=\dfrac{9}{15}= \dfrac{3}{5}$ ,

$CotA=\dfrac{AC}{BC}=\dfrac{9}{12}=}\dfrac{3}{4}$

$CscA=\dfrac{AB}{BC}=\dfrac{15}{12}= \dfrac{5}{4}$ .

Therefore correct answer is option B which is $SinA = \dfrac{4}{5}$ , $tanA = \dfrac{4}{3}$ , $SecA=\dfrac{5}{3}$ , $CosA=\dfrac{3}{5}$ , $CotA=\dfrac{3}{4}$ and $CscA=\dfrac{5}{4}$ .

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