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lozanna [386]
3 years ago
8

Find f’(x) when f(x)= 2x^2

Mathematics
2 answers:
Andru [333]3 years ago
6 0

Answer:

b) 4x

Step-by-step explanation:

f(x) = 2 {x}^{2}  \\ differentiantig \: w.r.t . \: x \\  {f'} (x) =  2 \times 2x \\ {f'}(x) =  4x \\

Romashka [77]3 years ago
5 0
I also got B choose B
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Step-by-step explanation:

4 0
3 years ago
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Substitution Method <br> y=x-4<br> y=4x-10
ira [324]

Answer:

x=2 and y= -2

Step-by-step explanation:

Substitute y=x-4 in second equation

x-4=4x-10

get x terms on one side and numbers on other sides

4x-x=10-4

3x=6

divide 3 on both sides

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4 0
2 years ago
Find the average rate of change between n=1 and n=3
Vitek1552 [10]

Answer:

there is not enough information to solve

Step-by-step explanation:

You need two ordered pairs to calculate the average rate of change.

Let's say the value of the function at n = 1 is a, and the value of the function at n = 3 is b, then the average rate of change from n = 1 to n = 3 is

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4 0
2 years ago
The position vector for a particle moving on a helix is
topjm [15]

Answer:

a) 25.15

b)

   x = 1

   y = t

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c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

6 0
3 years ago
If f(x) = 2x² + 5, then what is the remainder when f (x) is divided by x – 10?
photoshop1234 [79]

Answer:

Step-by-step explanation:

x - 10 = 0

x = 10

f(10) = 2*10² + 5 = 2*100 + 5 = 200 + 5

      = 205

Remainder = 205

3 0
3 years ago
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