Answer:
Musah's final point from the centre = 60.355 steps
Step-by-step explanation:
From the given information:
Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps west and finally 50 steps on a bearing of 315°
The sketch for this information can be seen in the attached file below.
How far west is Musah's final point from the centre?
In order to determine how far west is Musah's,
Let d be the distance of how far;
Then d = QR + RS cos θ
In the North West direction,
cos θ = cos 45°
d = 25 + 50( cos 45°)
d = 25 + 50(
)
d = 25 + 50( 0.7071)
d =25 + 35.355
d = 60.355 steps
Musah's final point from the centre = 60.355 steps
Blue triangle: perimeter is 4x+2+7x+7+5x-4, or, after simplification,
16x + 5
Red triangle: perim. is 2x-5+x+7+x+3 (and so on).
The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
Answer:
It is A
Step-by-step explanation:
I cant explain step by step I am in a rush but it is A