Ask question

Ask question

All categories

3 years ago

8

write an expression with (-1) as its base that will produce a positive product, and explain why your answer is valid

1 answer:

Marina CMI [18]3 years ago

5 0

Answer:

${( - 1)}^{2} \: = \: 1$

${( - 1)}^{0 } = \: 1$

Step-by-step explanation:

When we square a number (either positive or negative) the resultant no. is a positive one.

Also when a negative base has exponent 0 , the resultant number is +1 .

You might be interested in

Write an inequality for the following.<br> Jackie spent no more than $40 on a video

ANEK [815]

Answer:

x ≥ $40

Step-by-step explanation:

Jackie didn't spend more than $40 on a video.

x ≥ $40

7 0

3 years ago

what is the temperature in degrees celsius that is equivalent to a temperature of 40 degrees Fahrenheit

sdas [7]

4.4 in Celsius I’m pretty sure

3 0

3 years ago

Can someone please help me answer this?

posledela

It’s height x width 0.45 X 11= 4.95
Make sure not to put the unit behind it ;)

8 0

3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

7 0

4 years ago

Suppose that P(A|B)=0.2, P(A|B')=0.3, and P(B)=0.7. What is the P(A)? Round your answer to two decimal places (e.g. 98.76).

nata0808 [166]

Answer: $P(A) = 0.23$

Step-by-step explanation:

Given :

$P(A/B) = 0.2$

$P(A/B^{1})=0.3$

$P(B)= 0.7$

$P(A) = ?$

From rules of probability :

$P(A) = P(AnB) + P(A n B^{1})$ ........................... equation *

$P(A n B)$ can be written as $P(A/B)$ x $P(B)$

Also , $P(A/B^{1})$ can be written as $P(A/B^{1})$ x $P(B^{1})$

substituting into equation * , we have

$P(A) = P(A/B)$ $P(B) + P(A/B^{1})P(B^{1})$

since P(B) = 0.7, then $P(B^{1}) = 1 - P(B) = 0.3$

so , substituting each values , we have

$P(A) = (0.2)(0.7) + (0.3)(0.3)$

$P(A) = 0.14 + 0.09$

$P(A) = 0.23$

4 0

4 years ago