8a+3b-10+c^2when a =2,b=5,and c=4:
(8)(2)+(3)(5)−10+42
=16+(3)(5)−10+42
=16+15−10+42
=31−10+42
=21+42
=21+16
=37
Answer:
The answer is one
Step-by-step explanation:
-9/12= -.75
-7/4= -1.75
First step is to analyze input and output variables:
INPUT:
list of integers with name "values"
integer with name "p1"
integer with name "p2"
OUTPUT:
there is no output variable as in declaration of a method there is void
ANALYSIS:
"<span>int temp = values[p1]"
this line creates variable "temp" which is integer. then this line goes to the list "values" and takes value that is at position "p1" and stores it into variable "temp"
"</span><span>values[p1] = values[p2]"
this line </span>goes to the list "values" and takes value that is at position "p2" and stores it into variable that is at position "p1"
"<span>values[p2] = temp"
this line takes value of the variable "temp" and stores it into list values at position "p2"
Short explanation:
this code replaces values of the list at between positions p1 and p2</span>
