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2 years ago

Please helllpppp......

Mathematics

2 answers:

MrRissso [65]2 years ago

6 0

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2, thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

worty [1.4K]2 years ago

6 0

When you know a point (a,b) and the slope m of a line, you can write its equation as

$y-b=m(x-a)$

Plugging your values yields

$y-4=2(x-(-3)) \iff y=2x+10$

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2 years ago

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2 years ago

Read 2 more answers

Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y

DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

$\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}$

And:

$y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}$

If we apply these two to our initial expression, we can rewrite it as:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

$\sqrt{y^3} + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}$

Here we can use the second simplification again, to rewrite:

$\sqrt{y^3} = y*\sqrt{y}$

So, concluding, we have:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}$

Then the correct option is C.

8 0

2 years ago

How do you solve x/3>-1

Goryan [66]

x/3>-1

Isolate the x. Multiply 3 to both sides

(x/3)3 > -1(3)

x > -1(3)

x > -3

x > -3 is your answer

hope this helps

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Maru [420]

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2 years ago

Please helllpppp......​

Please helllpppp......