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3 years ago

Please helllpppp......

Mathematics

2 answers:

MrRissso [65]3 years ago

6 0

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2, thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

worty [1.4K]3 years ago

6 0

When you know a point (a,b) and the slope m of a line, you can write its equation as

$y-b=m(x-a)$

Plugging your values yields

$y-4=2(x-(-3)) \iff y=2x+10$

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aivan3 [116]

Answer:

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Step-by-step explanation:

Given equation is $a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]$

We have to prove that $a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]$

That is to prove that LHS=RHS

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$=a^3+ab^2+ac^2-a^2b-abc-a^2c+ba62+b^3+bc^2-ab^2-b^2c-abc+ca^2+cb^2+c^3-abc-bc^2-ac^2]$

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$=a^3+b^3+c^3-3abc$ =LHS

Therefore LHS=RHS

Therefore $a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]$

Hence proved.

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Please helllpppp......​

Please helllpppp......