a. There are four 5s that can be drawn, and 
ways of drawing any three of them. There are 
ways of drawing any three cards from the deck. So the probability of drawing three 5s is
In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of 
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability 
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of 
.
- - -
Note: 
is the binomial coefficient,
Answer:
0
Step-by-step explanation:
x = 2
2 x 3 = 6 + 5 = 11
2 - 2 = 0
Answer:
...
Step-by-step explanation:
Answer:
C and D are the same answers but one of those.
Step-by-step explanation:
Um, I got what Robert got, so by process of elimination, it must be C or D. I used multiplication, so it wasn't subtraction or addition. Meaning whatever a reciprocal is, I didn't do that.
Yes they do, in the grand aspect of things.
