Answer:
B and C
Step-by-step explanation:
they have -5x,   it doesn't really matter on their order
 
        
             
        
        
        
JIG is clockwise around the figure, as is DEF, so there is no reflection involved. The midpoint between any two corresponding vertices is (1, 4), so that is the center of rotation. Figure DEF is "upside down" from JIG, so rotation is 180°.
The 1st selection is appropriate.
        
                    
             
        
        
        
For the equation  F(x) = ax² + bx + c we have:
- maximum value if a<0
- minimum value if a>0
F(x) = -3x² + 18x + 3    ⇒  a = -3, b = 18
a < 0    ⇒   the function has a maximum value
Quadratic function has the maximum value (or minimum) at vertex of its parabola.
The maximum value is k at x=h where:   and  k = F(h)
  and  k = F(h)

Therefore:
<h3> 
The function has a maximum value of 30 at x = 3</h3>
 
        
             
        
        
        
119 <answer (check the solution in above pic)
hey friend i hope this answer is helpful
marl as brainliest if i deserve
 
        
        
        
It's a linear function. We need only two points to draw a graph.
We choose any values of x and calculate the value of y.

for x= 0 → y = 3(0) - 1 = 0 - 1 = -1 → (0, -1)
for x = 2 → y = 3(2) - 1 = 6 - 1 = 5 → (2, 5)

for x = 0 → y = 3(0) - 1/3 = 0 - 1/3 = -1/3 → (0, -1/3)
for x = 2 → y = 3(2) - 1/3 = 6 - 1/3 = 5 2/3 → (2, 5 2/3)