Use photo math to help you with this question
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
24
Step-by-step explanation:
1/2(x1+x2)c x1=3 , x2=5 , c=6
:- 1/2(3+5)6 ( BODMAS)
:- 1/2(8)6 divide 8 by 1/2
:- (4)6 multiply both of them and the result = 24
Answer:
poit 1 5 q
Step-by-step explanation:
Answer:
love your nails, can u bring it a bit closer tho?
Step-by-step explanation:
