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Diano4ka-milaya [45]

3 years ago

11

31 x 8,203 Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

2 answers:

Lelechka [254]3 years ago

6 0

Answer:

31 x 8,203 = 254,293

Step-by-step explanation:

alisha [4.7K]3 years ago

6 0

Answer:

254,293

Step-by-step explanation:

I punched it into a calculator

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Please help with these 2 questions!!

adell [148]

Hey there,

Question : <span>Steven had 24 pineapples. He sold 6 of them. What fraction of the pineapples did he sell?

Answer :
6 / 24 ----> divide by 6
= 1 / 4 (simplified version)

Question : </span><span>Nancy bought 8 m of string. She used 5/8 of string to make a flower pot hanger. How much of the string did she have left?

Answer :
8 - 5 / 8 = 7 3 / 8

Hope this helps :))

<em>~Top♥</em>
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5 0

2 years ago

Read 2 more answers

ANSWER AND EXPLAIN IF UR RIGHT ILL MARK U BRAINLIEST!!!

guapka [62]

Answer:

5

Step-by-step explanation:

B and D are congruent. Set them equal to each other.

15x + 5 = 16x - 2

x = 7

Plug into B.

15(7) + 5 = 110

180 - 110 = 70

12y + 10 = 70

12y = 60

60 / 12 = 5 = y

6 0

3 years ago

The original price is $75. She used a coupon code to receive a 20% discount. The web site applied a 10% service fee to the disco

ELEN [110]

-20% + 10 % = -10%

The ticket was less by 10 percent.

4 0

3 years ago

Original price: ?<br> Discount: 30%<br> sale price: 206.50

Lyrx [107]

11.875 thats your answer

5 0

3 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago