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Diano4ka-milaya [45]
2 years ago
11

31 x 8,203 Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Mathematics
2 answers:
Lelechka [254]2 years ago
6 0

Answer:

31 x 8,203 = 254,293

Step-by-step explanation:

alisha [4.7K]2 years ago
6 0

Answer:

254,293

Step-by-step explanation:

I punched it into a calculator

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For a-b, reduce to the least non-negative residue
Olenka [21]

Answer:

  a.  6

  b.  9

Step-by-step explanation:

a. The product modulo 7 can be found from the product of the individual numbers modulo 7:

  (88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7

  = (4·4·1·3) mod 7 = 48 mod 7 = 6

__

b. Powers of 4 mod 11 repeat with period 5:

  4 mod 11 = 4

  4^2 mod 11 = 5

  4^3 mod 11 = 9

  4^4 mod 11 = 3

  4^5 mod 11 = 1

So, 4^83 mod 11 = 4^3 mod 11 = 9

3 0
3 years ago
rob is asked to graph this system of equations: 6x + 2y = 5; y + 3x =2; how many times will the lines intersect? A. there is no
9966 [12]

Answer:

  C

Step-by-step explanation:

A and B are wrong and with D they wouldn't be lines so imma go with C.

Sorry if it's wrong.

6 0
2 years ago
The temperature was -14°F
sleet_krkn [62]

Answer:

-21F

Step-by-step explanation:

You basically count 14+7 equal 21 so -14-7 is -21.

8 0
2 years ago
Read 2 more answers
The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
3 years ago
4/5,3/10 =. Please help
KengaRu [80]

Answer:

The answer would be 0,0754716981

5 0
3 years ago
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