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lutik1710 [3]
3 years ago
12

A polygon is reflected across a line. The angles in the original figure are compared to the corresponding angles in the image to

see if they are congruent. Which factors does this depend upon?
Mathematics
2 answers:
irina [24]3 years ago
5 0
None. <span>They will always be congruent.</span>
Nana76 [90]3 years ago
4 0

Answer:

When a polygon is reflected about a line, the reflected figure will be exactly the mirror image of the original figure.

So, we can say that the shape and size of the new polygon will be exactly the same as the original polygon.

So, the corresponding angles  and corresponding sides, all will be same or identical.

Hence, the polygons will always be congruent.

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PLEAS HALP MEH&lt;<br> What angle measure is complementary to a 37° angle
Fynjy0 [20]
The angle measure would be 53°. 

Complementary angles add up to 90° so, if you're trying to find the other angle measure just subtract the angle measurement that you already know from 90.

90 - 37 = 53

Hope this helps! :)<span />
4 0
3 years ago
Read 2 more answers
A house appreciates (grows in value) about 6% each year. If the house is now worth 158,000, in about how many years will it be w
expeople1 [14]
200,000 = 158,000(1.06)^x
Divide both sides by 158,000
1.2658 = 1.06^x
Take the log of both sides and use the power rule to bring down the exponent (x) to the front.
log 1.2658 = x log 1.06
Divide both sides by log 1.06
log (1.2658)/log(1.06) = x
x = 4 years

CHECK
y = 158,000(1.06)^4
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8 0
3 years ago
What is the perimeter of the quadrilateral ABCD ?
Troyanec [42]

Answer:

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3 0
3 years ago
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the groun
agasfer [191]

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that \mu = 185, \sigma = 32

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of  Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 185}{32}

Z = -2.66

Z = -2.66 has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that p = 0.0039

5 parachutes, which means that n = 5

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

5 0
3 years ago
I really need help with this.
PolarNik [594]
A. X+8, y-4

Hope this helps and good luckkk :)
8 0
2 years ago
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