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3 years ago

I need help with this!!!

Mathematics

1 answer:

lidiya [134]3 years ago

8 0

I think it might be 40 have you tried

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FIND the inverse of f(x)= -6 -x^1/3<br><br> f^-1 (x) =

inna [77]

Answer:

$f^{-1}(x) = - (x+6)^3$

Step-by-step explanation:

Use the x-swap-y method to find the inverse:

$y = -6 -x^{1/3}\\x\leftrightarrow y\\x = -6-y^{1/3}\,\,\,\mbox{and solve for y:}\\-x-6=y^{1/3}\\(-(x+6))^{3}=y\\y = - (x+6)^3$

7 0

3 years ago

Need help ...what is the slope line passing through (-5,-3) and (-7,-12)

Mumz [18]

This should show you the answer!

5 0

3 years ago

Please answer question

Dmitry_Shevchenko [17]

The value of the expression $2\cos(t) + \tan^2(t)$ is 4 and the exact value of $\sin^{-1}(\sin(\frac{5\pi}{3}))$ is $\frac{5\pi}{3}$

<h3>How to determine the trigonometry expression?</h3>

The point on the unit circle is given as:

$P = (\frac 12, \frac{\sqrt{3}}2)$

A point on a unit circle is represented as: (x,y), such that:

cos(t) = x and sin(t) = y.

This means that:

$\cos(t) = \frac 12$

$\sin(t) = \frac{\sqrt 3}{2}$

Calculate tan(t) using:

$\tan(t) = \frac{\sin(t)}{\cos(t)}$

So, we have:

$\tan(t) = \frac{\frac{\sqrt 3}{2}}{1/2}$

Evaluate

$\tan(t) = \sqrt 3$

The expression is then calculated as:

$2\cos(t) + \tan^2(t) = 2 * \frac12 + (\sqrt 3)^2$

Evaluate each term

$2\cos(t) + \tan^2(t) = 1 + 3$

Evaluate the sum

$2\cos(t) + \tan^2(t) = 4$

Hence, the value of the expression $2\cos(t) + \tan^2(t)$ is 4

<h3>How to solve the arcsin expression?</h3>

The expression is given as:

$\sin^{-1}(\sin(\frac{5\pi}{3}))$

As a general rule, the arc sine of sine x is x.

This means that:

$\sin^{-1}(\sin(\frac{5\pi}{3})) = \frac{5\pi}{3}$

Hence, the exact value of $\sin^{-1}(\sin(\frac{5\pi}{3}))$ is $\frac{5\pi}{3}$

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

6 0

2 years ago

0.75(4x + 2) = 5 - (x + 1.5)<br> X =

djverab [1.8K]

Answer:

The answer is x=1/2 or x=0.5

7 0

3 years ago

Read 2 more answers

Reflection coordinate plane

Kruka [31]

(-2,-3)

Mirror the point across the x-axis. If it is at (-2,3) then the reflection would be (-2, -3)

5 0

3 years ago