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3 years ago

If BC=12 and CE=15 then what does BE equal?

Mathematics

1 answer:

MAXImum [283]3 years ago

5 0

BE = BC + CE
If BC=12 and CE=15 then BE = 12 + 15 = 27

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Solve 3x2 = −12x − 15. x = −4 ± 2i x = −4 ± i x = −2 ± 2i x = −2 ± i

diamong [38]

ANSWER

$x = - 2 \pm i$

EXPLANATION

We use the method of completing the squares.

The equation is
$3 {x}^{2} = - 12x - 15$

We rewrite the above equation to obtain;

$3 {x}^{2} + 12x = - 15$

We divide through by 3 to obtain;

${x}^{2} + 4x = - 5$

We add half the coefficient of
$x$

to both sides of the equation to get,

${x}^{2} + 4x + {2}^{2} = - 5 + {2}^{2}$

The right hand side is now a perfect square.

${(x + 2)}^{2} = - 1$

We now take square root of both sides to get;

$x + 2 = \pm \sqrt{ - 1}$

We add -2 to both sides,

$x = - 2 \pm \sqrt{ - 1}$

We simplify to obtain,

$x = - 2 \pm i$

3 0

4 years ago

PLEASE HELP

gayaneshka [121]

Area would be 66

You would simply multiple the width be the height to get your area!

5 0

3 years ago

Jaun has 105 feet of rope he needs to cut into sections 7/8 feet long . how many sections can be cut

AVprozaik [17]

The answer is 120 sections.

Here's an explanation:

The rope is 105 feet long, and each section needs to be 7/8 feet. So to find the number of sections, you need to divide 105 by 7/8. 105 divided by 7/8 gives you the quotient 120. So there are 120 sections.

5 0

4 years ago

9. A boy rides away from home in an automobile at the rate of 28 miles an hour and walks back at the rate of 4 miles an hour. Th

muminat

Answer:

9. A loebskesşbxksjlejs

4 0

3 years ago

1- find the first term= ?, 90, 540, 3240

Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0

3 years ago