First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
= - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts
Answer:
C. II, III, IV, and V.
Explanation:
Acid buffer is generally formed by the combination of a weak acid as well as the salt of the conjugate base.
Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.
On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.
When acid or base is added to buffer, it resists changes in the pH.
Therefore, option (C) is correct.
It should be B. All of the other choices are used often by abusers
Answer:
Production Of Steel Plastics and textiles
Explanation:
It is many more etc
Answer:
ΔH = 53.28 kJ
Explanation:
Solving this kind of problems is quite straight forward. What is need is to manipulate the reactions by multiplying the coefficients and reversing if necessary the reactions so that when we add the reactions together at the end we will arrive to the desired equation we need to obtain the enthalpy.
The reaction we need to calculate the enthalpy is
3C(s) + 3H2(g) → C3H6(g) ΔH = ?
If we take the 2nd reaction and multiply it by three, the inverse of first one multiplied by 1/2 and three times the 3rd we will be get the desired equation and its enthalpy:
3 C(s) + 3 O2(g) → 3 CO₂(g) ΔH= 3 x ( -393.51 kJ)
3 CO₂(g) + 3 H₂O(l) → C₃H₆(g) + 9/2 O₂(g) ΔH= 1/2 x ( 4182.6 kJ)
3 H₂(g) + 3/2 O₂(g) → 3 H₂O(l) ΔH= 3 x ( -285.83 kJ)
3C(s) + 3H2(g) → C3H6(g)
Notice how the mole O2 cancel because they are in diferent sides of the equation. Also we changed the changed of the second since we inverted it.
ΔH = 3 x ( -393.51 kJ) + 1/2 x ( 4182.6 kJ) + 3 x ( -285.83 kJ)
ΔH = - 1180.53 + 2091.3 - 857.49 = 53.28 kJ