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miss Akunina [59]
3 years ago
11

What is the density of fresh water

Chemistry
2 answers:
Nastasia [14]3 years ago
8 0

Answer:

Density of fresh water is the mass per unit volume of the fresh water.

Explanation:

The term Density can be defined as the mass per unit volume of a substance.

The mathematical expression for density;

{Density of fresh water}=\frac{\text{Mass}}{\text{Volume}}

The symbol for density is P, pronounced as "rho".

Also, the SI unit for measuring density is kg/m³.

The density of a material varies with temperature and pressure. This variation is typically small for solids and liquids but much greater for gases.

Anna [14]3 years ago
4 0

Answer:

about 1000 kg/m3

Explanation:

You might be interested in
A cup of hot water loses 265 cal
elixir [45]

Answer:

-1071 Joules

Explanation:

The Joule was introduced as the SI unit for energy in 1925.  One calorie is equal to approximately 4.184 joules(J).  This is a conversion factor that we can write two ways:

(1cal/4.184J) or (4.184J/1cal)

(265 cal)*(4.184J/1cal) = 1071 J

Since the energy is leaving the system, it should be written with a minus sign:  -1071J

7 0
2 years ago
Calculate the specific heat capacity for a 15.3-g sample of gold that absorbs 87.2 J when its temperature increases from 35.0 °C
diamong [38]

Answer:

The specific heat of gold is 0.129 J/g°C

Explanation:

Step 1: Data given

Mass of gold  = 15.3 grams

Heat absorbed = 87.2 J

Initial temperature = 35.0 °C

Final temperature = 79.2 °C

Step 2:

Q = m*c*ΔT

⇒ Q =the heat absorbed = 87.2 J

⇒ m = the mass of gold = 15.3 grams

⇒ c = the specific heat of gold = TO BE DETERMINED

⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C

87.2 J = 15.3g * c * 44.2°C

c = 87.2 / (15.3 * 44.2)

c = 0.129 J/g°C

The specific heat of gold is 0.129 J/g°C

4 0
4 years ago
What is the correct way to write 1,550,000,000 in scientific notation
aliina [53]
It would be 1.55x10 to the 9th
 hope that helps you
6 0
3 years ago
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
I need help ASAP! How many reactants and products are in each element according to the chemical equation above. Please explain t
Nikitich [7]
Answer: 1,4,1 for the reactants
3,1,4,1 for the products

Explanation:
The products are equal to the reactants because of the conservation of matter.
6 0
3 years ago
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