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adelina 88 [10]

2 years ago

8

Which force prevents protons from repelling each other inside a nucleus?

1 answer:

telo118 [61]2 years ago

5 0

Which force prevents protons from repelling each other inside a nucleus?

the gravitational force

the weak nuclear force

the electromagnetic force

<u>the strong nuclear force</u>

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A compound with a total of four carbons. A straight chain across the bottom of three carbons with all single bonds. There is a m

AleksandrR [38]

I know the answer. It is 2 straight chains. lLOL

6 0

3 years ago

Arada [10]

Answer:

The answer is NO

Explanation:

In every compound, the sum of oxidation number between the elements is 0.

In NO, nitrogen acts with +2 and oxygen as usual acts with -2
In N₂O₃, nitrogen acts with +3 and oxygen, -2
In NO₂, nitrogen acts with +4, and oxygen -2
In N₂O, nitrogen acts with +1, and oxygen -2

8 0

2 years ago

A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o

Andre45 [30]

Answer:

* $x_{CH_3OH}=0.0425$

* $\%m/m_{CH_3OH}=7.31\%$

* $m=2.46m$

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

$x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}$

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

$n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O$

Hence, mole fraction is:

$x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425$

Next, mass percent is:

$\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%$

And the molality, considering the mass of water in kg (0.185 kg):

$m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m$

Regards.

7 0

3 years ago

You have 0.5 L of air at 203 k in an expendable container at constant pressure. You heat the container to 273 k. What is the vol

avanturin [10]

Charles law states that for a fixed mass of gas at constant pressure the volume of the gas is directly proportional to the temperature in Kelvin scale

v1/T1 = v2/T2

Where v1 is volume and T1 is temperature at the first instance

v2 is volume and T2 is temperature at the second instance

Substituting the values in the equation

0.5 L / 203 K = v2 / 273 K

v2 = 0.672 L

The volume of Air after heating is 0.672 L

6 0

2 years ago

ILL GIVE BRAINLIEST! :).

fomenos

Option 2 is the correct answer

3 0

2 years ago