Answer:
The NaCl concentration will be 0.03 M.
Explanation:
Given data:
Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)
Initial concentration = M₁= 0.5894 M
Final volume = V₂= 1.20 L
Final concentration = M₂= ?
Solution:
By diluting the solution volume of solution will increase while number of moles of solute remain the same.
Formula:
Initial concentration × Initial volume = Final concentration × Final volume
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
M₂ = 0.5894 M × 0.05698 L / 1.20 L
M₂ = 0.0336 M /1.20
M₂ = 0.03 M
The answer is number 2. That releases massive amounts of radiation and by the way, that is how atomic bombs are made to detonate.
Answer:
1. 0.97 V
2.
Explanation:
In this case, we can start with the <u>half-reactions</u>:
With this in mind we can <u>add the electrons</u>:
<u>Reduction</u>
<u>Oxidation</u>
The reduction potential values for each half-reaction are:
- 0.69 V
-1.66 V
In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:
+1.66 V
Finally, to calculate the overall potential we have to <u>add</u> the two values:
1.66 V - 0.69 V = <u>0.97 V</u>
For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:
I hope it helps!
D. 350 J
Explanation:
Given parameters:
Force of pull = 70N
Distance = 5m
Unknown:
Workdone on the box = ?
Solution:
Workdone is defined as the force applied on a body to move it through a distance.
Work done = Force x distance moved
Work done = 5 x 70 = 350J
Learn more:
Work done brainly.com/question/9100769
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