Answer:
0.0187 M
Explanation:
Step 1: Write the balanced neutralization reaction
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
18.7 mL of 0.01500 M HCl react.
0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.
Step 4: Calculate the molarity of NaOH
2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.
[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M
Answer:
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Answer:
It would require 80 g of NaOH .
Explanation:
<span>First, divide the mass of N2O by it's molar mass of 46 g/mol to determine the number of moles of N2O, then multiply that number by two since there are two moles of N in each mole of the compound N2O. This results in a final answer of 9.78X10^-3 moles of N in 0.225g of N2O.</span>
Answer:
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Explanation:
