Answer:
what is the question
Step-by-step explanation:
Answer:

Step-by-step explanation:
The problem is:
<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>
<em />
This problem is about algebraic language. We just need to express the ordinaty language into an equation.
We know the words less means difference. So, let's call
Argos' weight and
Roco's weight. We can expresse the given problem as

Notice that we applied a difference due to the word "less" in the problem.
Therefore, Argo's weight is given by the expression

Answer:
<h2>
The answer is B. $8.82</h2>
Step-by-step explanation:
given data
mints $0.96 per pound
chocolates $4.70 per pound
lollipops $0.07 each
cost of each items based on the amount item
mints $0.96*0.75= 0.72
chocolates $4.70*1.5=7.05
lollipops $0.07*15=1.05
total cost= 0.72+7.05+1.05
total cost=$8.82
Answer:
surplus of 150$
Step-by-step explanation:
1853.68 + 178. times .249 = ......................owed at the end of the month
1450 +600 + 340 = $2390. * 12= $28 680. annually
..
30480 - 28680 = $1800. surplus at the end of the year divided by 12 = $150.00 monthly surplus
The value of h(t) when
is 10.02.
Solution:
Given function 
To find the value of h(t) when
:

Substitute
in the given function.


Now multiply the common terms into inside the bracket.

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64




= 10.02

Hence the value of h(t) when
is 10.02.