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Rina8888 [55]
3 years ago
11

11. If there are 8.24 x 1022 molecules of NaCl in a salt shaker, what is the mass of the salt?

Chemistry
1 answer:
vlada-n [284]3 years ago
6 0

Answer: 8.12 g NaCl

Explanation: Use Avogadro's number to find the number of m

moles of NaCl:

8.24x10²² molecules NaCl / 1 mole NaCl/ 6.022x10²³ molecules NaCl

= 0.14 mole NaCl

Next convert moles to grams NaCl using its molar mass;

0.14 mole NaCl x 58g NaCl / 1 mole NaCl

= 8.12 g NaCl

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10. In which of the following is the symbol for the ion and the total number of electrons it contains given correctly?
dalvyx [7]

Answer:

10. D

9. A

8. A or B

Explanation:

10. Calcium has 20 electrons, but the Calcium ion has 18 electrons.

9. The mass of electrons are negligible.

8. Electrons have a very small mass where some consider it to have no mass.

5 0
3 years ago
Rewrite the equation below using the correct conventions for stoichiometric coefficients. 2 BaCl2 + 2 H2SO4 → 2 BaSO4 + 4 HCl
vichka [17]

Answer:

BaCl2+H2SO4 \rightarrow BaSO4+2HCl

Explanation:

The given equation is:

2 BaCl2+2H2SO4 \rightarrow2BaSO4+4HCl

Based on the reaction stoichiometry:

2 moles of barium chloride (BaCl2) reacts with 2 moles of sulfuric acid (H2SO4) to form 2 moles of barium sulfate (BaSO4) and 4 moles of HCl

Although the reaction is balanced, the correct convention is to depict reactions in terms of the lowest molar ratio. Therefore the coefficients (2,2,4 and 4) can be divided by 2 to give:

BaCl2+H2SO4 \rightarrow BaSO4+2HCl

6 0
3 years ago
When nahco3 completely decomposes, it can follow this balanced chemical equation: 2nahco3 → na2co3 h2co3 determine the theoretic
BigorU [14]

Theoretical yield = 2.397

The product could be sodium carbonate

percent yield = 98.456%

When nahco3 completely decomposes, it can follow this balanced chemical equation:

2nahco3 → na2co3 h2co3

If the mass of the NaHCO3 sample is 3.80 g, we must use stoichiometry to calculate the theoretical yields of each of the products.

mass of NaHCO₃ = 3.80 g

molar mass of NaHCO₃ = 84 g/mol

so the no of moles of NaHCO₃ = 3.80/84 =  0.0452 mol

You see, one mole of sodium carbonate and one mole of hydrogen carbonate are produced from two moles of sodium bicarbonate.

so, the no of moles of sodium carbonate = 0.0452/2 = 0.0226 mol

∴ mass of sodium carbonate ( Na₂CO₃) = no of moles of Na₂CO₃ × molar mass of Na₂CO₃

=  0.0226 × 106 ≈ 2.397 g

no of moles of hydrogen carbonate = 0.0452/2 = 0.0226 mol

mass of the hydrogen carbonate ( H₂CO₃) = no of moles of H₂CO₃ × molar mass of H₂CO₃

= 0.0226 × 62 g = 1.401 g

mass of one of the products was measured to be 2.36 g , from above data, we can say it must be sodium carbonate because value is the nearest of 2.397 g.

percentage yield = experimental yield/theoretical yield × 100

here experimental yield of Na₂CO₃ = 2.36 g

and theoretical yield of Na₂CO₃ = 2.397 g

∴ % yield = 2.36/2.397 × 100 ≈ 98.456%

Therefore the percentage yield of the product is 98.456%

To learn more about percentage yield visit:

brainly.com/question/22257659

#SPJ4

6 0
2 years ago
How many sig figs are in 0.0003422
Ivenika [448]

Answer:

4

Explanation:

The zeros before a non zero digit do not count as significant figures so there are 4 sig figs in the number

5 0
3 years ago
Cerebrum is made of ____ matter? 4 letter word
katen-ka-za [31]
Gray matter hope this helps!
7 0
3 years ago
Read 2 more answers
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