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kodGreya [7K]
2 years ago
11

Which step accurately describes how to measure the final burette volume?

Chemistry
2 answers:
8090 [49]2 years ago
4 0
To accurately measure the final volume of a solution in a burette, it is important that you read of the measurement in the lower meniscus like for water and for substances like mercury you read it on the upper meniscus. This is the standard way of reading volumes in laboratory apparatus. Also, it should be that the apparatus standing vertically in a plain surface.
LekaFEV [45]2 years ago
3 0

Answer:

The precision to measure a volume in a burette will depend on the shape of the meniscus that forms the liquid. In the case of a concave meniscus, its reading will be made at the lowest height of the liquid surface. This point should touch the upper edge in the division of the burette scale. In the case of a convex meniscus, its reading will be made at the highest height of the liquid surface. This point should touch the bottom edge in the burette scale division.

Explanation:

The accuracy when reading the correct volume in a burette depends on the type of meniscus. If the molecules of a liquid have a greater attraction to the glass wall, the meniscus will have a concave shape, for example, aqueous solutions. A requirement to measure exactly is the adjustment of the meniscus. As stated before, if the meniscus shape is concave, the volume will be read at the lowest height of the liquid surface. If the meniscus is convex, the volume will be taken at the highest height of the liquid surface. Convex menisci are formed by substances such as mercury.

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One mole of N2 gas at STP will occupy what volume?
Sergio [31]

Answer:

If you have 1 mole of N2 (or any other gas for that matter) under STP conditions it will occupy a volume of 22.4 L. This is known as the “standard molar volume”. So, if you know the number of moles of gas that you have, you can use a simple ratio (1 mole : 22.4 L) to determine the volume of the gas

Explanation:

8 0
3 years ago
Read 2 more answers
The main reasons why ch4 has a higher vapor pressure at a given temperature when compared to ch3cl is that ch4 and . 2. the main
ale4655 [162]
Vapour pressure of system depends upon intermolecular forces of interaction. Greater the interaction, larger will the vapour pressure, more will be the boiling point.

Answer 1: 
CH4 stands for methane and CH3Cl named as chloromethane. In methane, all the valances of C atom is satisfied by hydrogen. Due to this, it has zero dipole moment. While, in case of CH3Cl, one of the valance is satisfied by an electronegative element i.e. Cl. Due to this, it acquires a polar character. Also, it has a net dipole moment. Due to this, CH3Cl exhibits dipole-dipole intermolecular force of attraction, which is absent in CH4.  Hence, CH3Cl has lower vapor pressure as compared to CH4. 

Answer 2: 
H2CO is named as formaldehyde, while CH3OH is named as methyl alcohol. In case of methyl alcohol, hydrogen atom (an electropositive atom) is bonded to oxygen (a highly electronegative element). This is absent in case of formaldehyde. Due the this, methyl alcohol as greater polarity as compared to formaldehyde. Due the greater polarity, vapour pressure of CH3OH is less as compared to H2CO. 

Answer 3:
<span>CH3CH2CH2OH is named as propanol or propyl alcohol. Propyl alcohol, has longer chain length as compared to methyl alcohol (CH3OH). Both of this compounds has a polar character due to presence of -OH functional group. However, due to long chain of propyl alcohol, polar character increases. This can be attributed the +I effect of CH3 group. Due to this, intermolecular forces of interaction are higher in propanol, thereby decreasing its vapor pressure as compared to methanol. </span>
8 0
3 years ago
What is the pH of a 0.1 M phosphate buffer (pKa = 6.86) that contains equal amounts of acid and conjugate base?
Anvisha [2.4K]

Answer : The pH of a 0.1 M phosphate buffer is, 6.86

Explanation : Given,

pK_a=6.86

Concentration of acid = 0.1 M

Concentration of conjugate base (salt) = 0.1 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=6.86+\log (\frac{0.1}{0.1})

pH=6.86

Therefore, the pH of a 0.1 M phosphate buffer is, 6.86

4 0
3 years ago
A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and
vladimir2022 [97]

Answer:

C_{7} H_{5}N_{3}O_{6}

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC

0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\

Analogously for hydrogen:

0.0310gH_{2}O have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N

now

\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}

and you can multiply by  5   to obtain: C_{7} H_{5}N_{3}O_{6}

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3 years ago
How is energy transfer connected to your life
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Answer:

Baking, microwave, heating system for your house, water boiler, fridge.

4 0
2 years ago
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