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4 years ago

22. Naturally occurring hydrogen consists of three isotopes, hydrogen-1 (1.07 u)

Chemistry

1 answer:

astra-53 [7]4 years ago

6 0

Answer:

The answer to your question is: a. Hydrogen-1

Explanation:

Hydrogen-1 (1.07 u)

Hydrogen-2 (2.02 u)

Hydrogen-3 (3.01 u)

Periodic table says that H has an atomic mas of 1.008

Then, the reported atomic mass is closer to the mass of the smaller isotope, so Hydrogen-1 must be present in larger percentage.

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Whats between -999 and 1000

Doss [256]

Hello!

Numbers from -998 and 999 are in between -999 and 1000.

I hope this was helpful! c:

7 0

3 years ago

A 187.4g sample of C3H5(NO3)3 decomposes to produce carbon dioxide, water, diatomic oxygen and diatomic nitrogen.

Delicious77 [7]

Answer:

See Explanation

Explanation:

The equation of the reaction is as follws;

4 C3H5(NO3)3 (l) → 12 CO2 (g) + 10 H2O (l) + 6 N2 (g) + O2 (g)

Number of moles of C3H5(NO3)3 = 187.4g /227 g/mol = 0.82555 moles

If 4 moles of C3H5(NO3)3 yields 12 moles of CO2

0.83 moles of C3H5(NO3)3 yields 0.82555 * 12/4 = 2.47665 moles of CO2

mass of CO2 produced = 2.47665 moles * 44 g/mol = 108.95 g of CO2

4 moles of C3H5(NO3)3 yields 10 moles of water

0.83 moles of C3H5(NO3)3 yields 0.82555 * 10/4 = 2.063875 moles of water

Mass of water = 2.063875 moles of water * 18 g/mol = 37.16 g

4 moles of C3H5(NO3)3 yields 1 mole of O2

0.83 moles of C3H5(NO3)3 yields 0.82555 * 1/4 = 0.2063875 moles of O2

Mass of O2 = 0.2063875 moles of O2 * 32 g/mol = 6.6 g

4 moles of C3H5(NO3)3 yields 6 moles of N2

0.83 moles of C3H5(NO3)3 yields 0.82555 * 6/4 = 1.238325 moles of N2

Mass of N2= 1.238325 moles of N2 * 28 g/mol = 34.67 g

To verify the law of conservation of mass, the total sum of mass of products must equal the sum of the mass of reactants. Thus;

108.95 g + 37.16 g + 6.6 g + 34.67 g = 187.4 g

The law of conservation of mass has been proven!

6 0

3 years ago

Hdhdhzjzjzj which??????????????????

dsp73

Answer:

I think it’s D but not sure

Explanation:

8 0

3 years ago

Ted likes to run long distances. He can run 20 km 20 km20, start text, space, k, m, end text in 95 9595 minutes. He wants to kno

balu736 [363]

Answer:

The distance in kilometer that Ted will go if he runs at the same pace for 285 minutes is 60km

Step-by-step explanation:

It was given that Ted Ted runs 20 km in 95 minutes, so for us to know how many kilometers he runs at the same pace for 285 minutes by using proportion.

For Ted to run 20 km in 95 minutes.

$Speed=Distance/Time$

where given distance= 20km

Given time =95minutes

Speed=20/95 .............eqn(1)

To calculate the distance in kilometers Ted will go if he runs at the same pace for 285 minutes, then

Speed= K/225 ...............eqn(2)

Let us represent distance with 'K'

Given time 225minutes

Equating eqn(1) and eqn(2)

Hence the proportion model that Ted could use in modelling this situation is this;

$20/95=K/225$

Cross multiply

K×95=20×225

$K=60$

The distance in kilometer that Ted will go if

he runs at the same pace for 285 minutes is 60km

3 0

3 years ago

Joe’s cells can’t convert food energy effectively into energy they can use. As a result, he gets extremely tired, has weak legs,

Bad White [126]

The nucleus is effected

Explanation: The nucleus is the main part of it gets weak they all get weak

5 0

4 years ago

Read 2 more answers