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laila [671]
3 years ago
15

Please help! Correct answer only!

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

$7.50

Step-by-step explanation:

Since there is a 50% chance that the card is odd, the expected payoffs would be $15 * 50%=0.5*15=7.5. Hope this helps!

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&
Nady [450]

Answer:

the answer is B and C

Step-by-step explanation:

9x4=36

6x6=36

6 0
2 years ago
She runs for 6.4 miles at a speed of 4 miles per hour. For how many hours does she run?
Alexxandr [17]
<span>4 miles per hour
</span><span>6.4 miles ...? hours

6.4 / 4 = 1.6 hours

answer
she runs 1.6 hours for 6.4 miles</span>
6 0
3 years ago
Read 2 more answers
Katie can swim 3 laps in the pool on 6 minutes. How many minutes will it take her to swim 10 laps?
storchak [24]

3 laps : 6 minuets

6/3 = 2

3/3 = 1

1 lap : 2 minuets

1 * 10 = 10

2 * 10 = 20

10 laps : 20 minuets

8 0
3 years ago
Three brothers share a 5 gigabyte (gb) family data plan on their cell phones. One month. Aaron used. 2.3gb, Brian
zavuch27 [327]

Step-by-step explanation:

\frac{5gb}{110}  =  \frac{2.3gb}{x}

→ x = 2.3 ×110÷5 = 50.6 $ Aaron pay

→Brian = 1.1 × 110 ÷5=24.2$

Caleb = 110 - ( 24.2 + 50.6 ) = 110 -74.8 = 35.2$

7 0
2 years ago
fair coin is tossed three times. What is the probability that all three tosses land on heads,given that:(a) the first toss lands
maxonik [38]

Answer:

(a) The probability that all three tosses land on heads given that the 1st toss lands on Heads is \frac{1}{4}.

(b) The probability that all three tosses land on heads given that at least one toss lands on heads is \frac{1}{7}.

Step-by-step explanation:

The sample space of tossing 3 coins is:

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} = 8 outcomes.

(a)

The sample space such that the 1st toss lands on Heads is:

S₁ = {HHH, HHT, HTH, HTT} = 4 outcomes.

The probability that all three tosses land on heads given that the 1st toss lands on Heads is:

P (3 Heads | 1st toss is Heads) = \frac{P(3\ Heads\ \cap \ 1st\ toss\ is\ Heads)}{P(1st\ toss\ is\ Heads)}

                                                  =\frac{\frac{1}{4} }{\frac{4}{8} } \\=\frac{1}{8}\times \frac{8}{4}\\  =\frac{1}{4}

Thus, the probability that all three tosses land on heads given that the 1st toss lands on Heads is \frac{1}{4}.

(b)

The sample space such that at least one toss lands on heads is:

S₂ = {HHH, HHT, HTH, THH, HTT, THT, TTH} = 7 outcomes

The probability that all three tosses land on heads given that at least one toss lands on heads is,

P (3 Heads | At least 1 Heads) =\frac{P(3\ Heads\ \cap\  At\ least\ 1\ Heads)}{P( At\ least\ 1\ Heads)}

                                                  =\frac{\frac{1}{7} }{\frac{7}{8} } \\=\frac{1}{8}\times \frac{8}{7}\\  =\frac{1}{7}

Thus, the probability that all three tosses land on heads given that at least one toss lands on heads is \frac{1}{7}.

4 0
2 years ago
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