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Semenov [28]
3 years ago
11

Score: U of 1 pt

Mathematics
2 answers:
fredd [130]3 years ago
6 0

Answer:

x+y =90

x-y=42

2x=132

x=66

y=24

Anit [1.1K]3 years ago
5 0

Answer:

24° and 66°

Step-by-step explanation:

Complementary angles sum to 90°

let the larger angle be x then the smaller angle is x - 42 and their sum is

x + x - 42 = 90, that is

2x - 42 = 90 ( add 42 to both sides )

2x = 132 ( divide both sides by 2 )

x = 66 and x - 42 = 66 - 42 = 24

The smaller angle is 24° and the larger angle is 66°

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Dovator [93]
The answer is point.
3 0
3 years ago
Question 9
True [87]

Answer:

17

Step-by-step explanation:

m<1 = (4x + 2)

m<3 = (5x - 15)

To find the value of x, we need to generate an equation.

<1 and <3 are vertical angles. Vertical angles are congruent. Therefore:

m<1 = m<3

(4x + 2) = (5x - 15)

Use this equation to solve for x

4x + 2 = 5x - 15

Subtract 5x from both sides

4x + 2 - 5x = 5x - 15 - 5x

-x + 2 = -15

Subtract 2 from both sides

-x + 2 - 2 = -15 - 2

-x = -17

Divide both sides by -1

x = 17

5 0
3 years ago
What is the value of x in the linear equation below?<br><br><br> 4+3x-ax=9-7x+bx
Furkat [3]

Answer:

x = 5/(10 - a - b)

Step-by-step explanation:

Solve for x:

4 + 3 x - a x = 9 - 7 x + b x

Collect in terms of x:

x (3 - a) + 4 = 9 - 7 x + b x

Collect in terms of x:

x (3 - a) + 4 = x (b - 7) + 9

Subtract (b - 7) x + 4 from both sides:

x (10 - a - b) = 5

Divide both sides by 10 - a - b:

Answer:  x = 5/(10 - a - b)

7 0
3 years ago
A mining company estimates that the marginal cost of extracting x tons of copper ore from a mine is 0.6 + 0.008x, measured in th
Serhud [2]

Answer:

The cost of extracting the first 50 tons of copper is $151,000.

Step-by-step explanation:

Start-up costs of $150,000.

For the 50 tons of cooper.

C(x) = 0.6 + 0.008x

So

C(50) = 0.6 + 0.008*50 = 1

1 thousand dollars.

So

$150,000 + $1,000 = $151,000

The cost of extracting the first 50 tons of copper is $151,000.

8 0
3 years ago
Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
4 years ago
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