If the amount of monkeys is m, lions is a, and lizards is b, then a+b+m=151, 17+a=m (since there are 17 more monkeys than lions), and 30+a=b. Substituting those values in (17+a=m and 30+a=b), we have 30+17+a+a+a=151=47+3a. Subtracting 47 from both sides, we get 104=3a. Next, we can divide both sides by 3 to get 104/3=a (the number of lions), 104/3+17=the number of monkeys, and 104/3+30=the number of lizards. Somehow we end up with a fraction (not a whole number), so there are 2/3rds of monkeys floating around using this logic.
Answer:
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Answer:
b will the correct answer plzz lock b and win 1 lakh
F, D, C
F: 5 x 3 = 15
D: 7 x 3= 21 - 2 = 19
C: 5 x 3 = 15 + 6 = 21
5(x^2+8x)=14
5(x^2+8x+16)=5(x^2+8x)+5*16=5(x^2+8x)+80=14+80=94
The corect answer is the second
