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Hatshy [7]
3 years ago
13

Express the sum in the simplest form 2y/y+2 + 4/y+2

Mathematics
2 answers:
Reil [10]3 years ago
8 0

Answer:

Step-by-step explanation:

2y/y + 2 + 4/y+2

2y/2y + 4/2y

1y + 2y

3y

nalin [4]3 years ago
7 0

Answer:

2

Step-by-step explanation:

2y                 4

------------ + ------------

y +2              y+2

Since the denominators are the same, we can add the numerators

2y+4

-----------

y+2

Factor a 2 out of the numerator

2 (y+2)

--------------------

y+2

Cancel the y+2 out of the numerator and denominator

2

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Umm what is this?????​
schepotkina [342]

Answer: The correct answer is 1/2 ÷ 1/11.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
6x − 3y = 7, −2x + y = −8 <br><br> x=?<br> y=?
kap26 [50]

Answer:

no solution

Step-by-step explanation:

6x - 3y = 7 → (1)

- 2x + y = - 8 → (2)

multiplying (2) by 3 and adding to (1) eliminates the variables

- 6x + 3y = - 24 → (3)

add (1) and (3) term by term

0 + 0 = - 17

0 = - 17 ← false statement

This indicates the system has no solution

5 0
2 years ago
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Pls helppp! tysmmmm!!
Margaret [11]
I believe it would be 29 because a supplementary angle is 2 angles that equal 180 so I would think to do 189-151=29
5 0
3 years ago
Carl and Dennis are brothers. The sum of their ages is 29. In 6 years' time Carl will be the same age as Dennis was 3 years ago.
lorasvet [3.4K]

Carl present age is 10 years while Dennis present age is 19 years.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent Carl present age and y represent Dennis present age, hence:

x + y = 29   (1)

Also:

After 6 years:

x + 6 = y - 3   (2)

From both equations:

x = 10, y = 19

Carl present age is 10 years while Dennis present age is 19 years.

Find out more on equation at: brainly.com/question/2972832

4 0
2 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
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