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Ksju [112]
3 years ago
13

Water's unique properties, including its high heat capacity, high density, high boiling point and a solid phase that is less den

se than its liquid phase, can best be attributed to:______
A) Its formula, H2O.
B) The covalent oxygen-hydrogen bonds in the molecule.
C) The shape of the molecule.
D) The polarity of the molecule and hydrogen bonding between the molecules.
Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer: Option (D) is the correct answer.

Explanation:

As the chemical formula of water is H_{2}O and due to the difference in electronegativity of hydrogen and oxygen atom there is formation of partial positive charge on hydrogen and partial negative charge on oxygen atom.

As a result, polarity arises on water molecule.

Also, there exists hydrogen bonding between molecules of water which is also responsible for providing unique properties to water.

Thus, we can conclude that water's unique properties, including its high heat capacity, high density, high boiling point and a solid phase that is less dense than its liquid phase, can best be attributed to the polarity of the molecule and hydrogen bonding between the molecules.

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g A 0.4395 g sample of aluminum reacts according to our experiment to produce alum. 5.1629 g of dried alum crystals are recovere
Alex

Answer:

92.75%

Explanation:

The overall chemical equation for the reaction in the preparation of alum from the aluminium can be expressed as:

\mathtt{2Al + 2KOH + 4H_2SO_4 +2H_2O   \to 2KAl(SO_4)_2 2H_2O +3H_2}

From above; we will see that 2 moles of Aluminium react with sulphuric acid and water to produce 2 moles o aluminium alum.

Therefore, the theoretical yield can be determined as:

=0.4395 \ g Al \times \dfrac{1 \ mol \ Al}{27 \ g Al }\times \dfrac{2 \ mol \ KAl(SO_4)_2}{2 \  mol \ Al}\times \dfrac{294.23 \ KAl(SO_4)_2}{1 \ mol \ KAl(SO_4)_2}

= 4.789g of KAl(SO_4)_2

To find the percent yield, we need to divide the actual yield by the theoretical yield and then multiply it with 100.

∴

percent yield = ( mass of alum(g)/theoretical yield(g) ) × 100

percent yield = ( 4.789g / 5.1629g ) × 100%

percent yield = 0.9275 × 100%

percent yield = 92.75%

Thus, the percent yield of the experiment 92.75%

8 0
3 years ago
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