How many moles are in 525 g of ammonia, NH3? 8940.75 M 0.03 M 30.83 M

Chemistry

2 answers:

victus00 [196]2 years ago

3 0

Answer:

30.83 M

Explanation:

17.03052 re in one mole. So, if you multiply it by 30.83, you will get 535 g of ammonia.

In fact, the detailed answer is 30.827009392549122.

Zielflug [23.3K]2 years ago

3 0

Answer:30. 83

Explanation:

17.03052 re in one mole. So, if you multiply it by 30.83, you will get 535 g of ammonia.In fact, the detailed answer is 30.827009392549122.

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Which of the following describes the stage that occurs after condensation in the water cycle?

NISA [10]

Answer:

Precipitation

Explanation:

There are four main stages in the water cycle. They are evaporation, condensation, precipitation and collection. Let's look at each of these stages. Evaporation: This is when warmth from the sun causes water from oceans, lakes, streams, ice and soils to rise into the air and turn into water vapour (gas).

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3 years ago

The ratio of nitrogen to oxygen by mass in NO is 7.0:8.0. Identify the ratio of nitrogen to oxygen by mass in NO2 and N2O7 .

Rus_ich [418]

This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.

<h3>Mass ratios:</h3>

In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:

$\frac{14}{16}=\frac{7.0}{8.0}$

Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:

$NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\
\\
N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}$

Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively

Learn more about atomic masses: brainly.com/question/5566317

3 0

2 years ago

Calculate the molarity of a solution consisting of 25.0 g of KOH in 3.00 L of solution.

melomori [17]

Answer:

0.15M

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

You need to calculate the number of moles from the given grams. The molar mass of KOH is (39.098+ 16 +1.008)= 56.106g. To calculate the mols of KOH, $\frac{25.0g}{1}$ × $\frac{1 mol}{56.106g}$ = 0.44558... mol, you see that the grams unit cancel out leaving you with mol as the unit.