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mezya [45]
3 years ago
9

What kind of bond is created by a week electrical attraction between polar molecules

Chemistry
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer : The dipole-dipole interaction.

Explanation : The kind of bond that is created by a weak electrical attraction between two polar molecules is dipole-dipole interaction.

The type of force which occurs between the positive end of one molecule and the negative end of another molecule: is dipole-dipole interaction.

For better understanding, please refer the attachment.

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Where are you in the process of finding your purpose?
sp2606 [1]
I haven’t yet, still working on it though
7 0
3 years ago
What volume of 0.555M KNO3 solution would contain 12.5 g of solute
Lorico [155]

The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.

<h3>What is the relationship between mass of solute and concentration of solution?</h3>

The mass of solute in a given volume of solution is related by the formula below:

  • Molarity = mass/(molar mass * volume)

Therefore, volume of solution is given by:

Volume = Mass /molarity * molar mass

Molar mass of KNO₃ = 101 g/mol

Volume = 12.5/(0.555 * 101)

Volume = 0.223 L or 223 mL

In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.

Learn more about molarity and volume at: brainly.com/question/26873446
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3 0
1 year ago
Why are scientists now more excited about sound levitation than they had been previously?
Olenka [21]

Answer:

Acoustic tractor beams use the power of sound to hold particles in mid-air, and unlike magnetic levitation, they can grab most solids or liquids even small insects. For the first time engineers have shown it is possible to stably trap objects larger than the wavelength of sound in an acoustic tractor beam. This discovery could enable the manipulation of drug capsules or micro-surgical implements within the body. The discovery could even lead to levitating humans.

Explanation:

3 0
3 years ago
Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress
ElenaW [278]

Answer:

(a) W_{isoentropic}=8.125\frac{kJ}{mol}

(b) W_{polytropic}=7.579\frac{kJ}{mol}

(c) W_{isothermal}=5.743\frac{kJ}{mol}

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant k should be computed for air as an ideal gas by:

\frac{R}{Cp_{air}}=1-\frac{1}{k}  \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\

0.2856=1-\frac{1}{k}\\\\k=1.4

Next, we compute the final temperature:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K

Thus, the work is computed by:

W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}

(b) In this case, since n is given, we compute the final temperature as well:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K

And the isentropic work:

W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}

Regards.

8 0
3 years ago
The following equation is balanced correctly. 4C2H6 + 7O2 --&gt; 6H2O + 4CO2<br> True <br> False
Ostrovityanka [42]

Answer: False

Explanation:

4C2H6 + 7O2 --> 6H2O + 4CO2

8 Carbons on the reactant side, but 4 Carbons on the Product

24 Hydrogens on Reactant, 12 H on product

But Oxygen is balanced, 14 on each side

4 0
3 years ago
Read 2 more answers
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