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ozzi
3 years ago
8

Weathering of rock and sedimentation ultimately lead to the formation of___

Chemistry
2 answers:
Inga [223]3 years ago
6 0
Weathering of the rock and sedimentation are decomposition processes. Through time, the minerals in the rocks soften due to pressure and heat. So, they crumble down and reduce in terms of size. Once they do, they become sand or part of the soil. So, the answer is A.
nydimaria [60]3 years ago
3 0

Answer:

soil

Explanation:

You might be interested in
An element, X, can form a chloride (XCl3) and an iodide (XI3). The chloride can be converted quantitatively into the iodide when
Arlecino [84]

Answer : The chemical symbol for this element is, (La)

Explanation : Given,

Mass of XCl_3 = 0.760 g

Mass of XI_3 = 1.610 g

The given chemical reaction is:

2XCl_3+3I_2\rightarrow 2XI_3+3Cl_2

First we have to calculate the moles of XCl_3 and XI_3.

\text{Moles of }XCl_3=\frac{\text{Mass of }XCl_3}{\text{Molar mass of }XCl_3}

Molar mass of Cl = 35.5 g/mole

Let the molar mass of element 'X' be, M

\text{Moles of }XCl_3=\frac{0.760}{[M+3(35.5)]}

and,

\text{Moles of }XI_3=\frac{\text{Mass of }XI_3}{\text{Molar mass of }XI_3}

Molar mass of I = 126.9 g/mole

Let the molar mass of element 'X' be, M

\text{Moles of }XI_3=\frac{1.610}{[M+3(126.9)]}

From the balanced chemical reaction we conclude that,

The moles of ratio of XCl_3 and XI_3 is, 1 : 1

That means,

\frac{0.760}{[M+3(35.5)]}=\frac{1.610}{[M+3(126.9)]}

\frac{0.760}{[M+106.5]}=\frac{1.610}{[M+380.7]}

M=138.667g/mol

From this we conclude that the element (X) is lanthanum (La) that has molecular weight, 138.667 g/mol.

Hence, the chemical symbol for this element is, (La)

6 0
4 years ago
What is the difference between a chemical process and and physical process
Flauer [41]

Answer: there is  no real difference between the two.

Explanation:

some teachers just like to explain how a chemical reaction is anything involved with chemicals and any other process is just explained as a physical process

8 0
4 years ago
Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 783.5-g sam
anastassius [24]
First, is to solve the molar mass of the herbicide, with a formula
<span>C3H8NO5P
C3 = 12 ( 3 ) = 36
H8 = 1 ( 8 ) = 8
N = 14
O5 =  16 ( 5 ) = 80
P = 31
so in total the molar mass of </span><span>C3H8NO5P is 36 + 8 + 14 + 80 + 31 = 169 g/mol

number of moles = 783.5 g ( 1 mol / 169 g)
number of moles = 4.64 mol </span><span>C3H8NO5P</span>
8 0
3 years ago
What will happen if pressure is increased on the system?
andrew11 [14]
It depends on the system if there are more moles of gas on the left and you increase the pressure the yield of a product will increase as the equilibrium moves to the side with the fewest gas molecules

if the right hand side has more moles of gas and you increase the pressure the yield will decrease as the equilibrium shifts to the left hand side where there are more gas moles 

hope that helps
5 0
3 years ago
1) If 0.193 grams of toluene is dissolved in 2.532 grams of p-xylene, what is the molality of toluene in the solution?2) If a fr
AveGali [126]

Answer:

The value of K_f for xylene is 4.309°C/m.

The molar mass of pentane using this data is 73.82 g/mol.

Explanation:

\Delta T_f=K_f\times \frac{\text{Amount of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent(kg)}}

where,

\Delta T_f =depression in freezing point

K_f = freezing point constant  

we have :

1) freezing point constant  for xylene = K_f =?

Mass of toluene = 0.193 g

Mass of xylene = 2.532 kg = 0.002532 kg ( 1 g =0.001 kg)

\Delta T_f=3.57^oC

3.57^oC=K_f\times \frac{0.193 g}{92 g/mol\times 0.002532 kg}

K_f=4.309^oC/m

The value of K_f for xylene is 4.309°C/m.

2)

Mass of pentane = 0.123 g

molar mass of pentame= M

Mass of xylene = 2.493 g =  0.002493 kg

Freezing point Constant of xylene = K_f=4.309^oC/m

2.88^oC=4.309^oC/m\times \frac{0.123g}{M\times 0.002493 kg}

M = 73.82 g/mol

The molar mass of pentane using this data is 73.82 g/mol.

5 0
3 years ago
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