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iVinArrow [24]
3 years ago
12

Two colleagues are measuring the melting point of a substance. They observe two ranges of melting point, at 134-137 °C and 132-1

36 °C. What are the possible reasons that lead to two different values with exactly the same sample?
Chemistry
1 answer:
marissa [1.9K]3 years ago
6 0

Explanation:

impurities affect both melting point and boiling point

in the case of melting point it lowers the melting point

so I guess one of the samples Ie contained impurities

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Actually, there are four kinds of reptile motion: 

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What 2 ways that humans have contributed to desertifaction
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Deforestation and inappropriate agriculture otherwise known as over farming are factors of and causes of desertification. 
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3 years ago
I need the answers to this and to see if what I put is right so far
klemol [59]

1) B+3 is ok. The exercise already put B+3. What

-------------------------------------------------------------------------------------------------------------------

2) Ge is a neutral atom because it doesn't have any charge.

Germanium has 32 electrons and 32 protons because its atomic number is 32.

Be careful with that.

Neutral atoms have the same numbers of electrons and protons.

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3)

5 0
11 months ago
This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. this part contains a
Masja [62]

The amount of heat transferred in and out of the system is measured by calorimetry. The thermometer in the calorimeter is used to measure the temperature.

<h3>What are the parts of the calorimetry device?</h3>

The thermometer (A) is a device used to measure the final and the initial temperature of the water or any other liquid in a system. A metal vessel is a place where the reaction mixture is present.

In-vessel (B), water, and metal are placed before the beginning of the experiment. The styrofoam cup or the outer metal vessel (C) insulates the instrument, from regulating the heat transformation.

Therefore, part A measures the temperature of the reaction mixture.

Learn more about insulated containers here:

brainly.com/question/866735

3 0
2 years ago
What is the final temperature of a 34.2 g of water initially at 282 K that has been heated with 2.71 kJ of energy?
lana66690 [7]

Answer: The final temperature of copper is  

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

                                       …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

                                   …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

So the value of Q can b calculated as follows:

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is .

Substitute these values in equation (2).

The temperature change  can be calculated as follows:

                         …… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

                      …… (4)

The value of  is .

The value of  is  

Substitute these values in equation (4).

So the final temperature of copper is .

7 0
3 years ago
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