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iVinArrow [24]
3 years ago
12

Two colleagues are measuring the melting point of a substance. They observe two ranges of melting point, at 134-137 °C and 132-1

36 °C. What are the possible reasons that lead to two different values with exactly the same sample?
Chemistry
1 answer:
marissa [1.9K]3 years ago
6 0

Explanation:

impurities affect both melting point and boiling point

in the case of melting point it lowers the melting point

so I guess one of the samples Ie contained impurities

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What organelle of a prokaryotic cell contains genetic information?
vlada-n [284]
There is actually no membrane bounded or enclosed organelle that contain the genetic content and or information within a prokaryote. In bacteria, for instance the bacterial genome, which is that of a enclosed single double stranded circular DNA molecule is associated with histone like proteins and found within the cytoplasmic region of a cell in an irregular manner. It is termed the nucleoid.
4 0
2 years ago
The enthalpy of vaporization of liquid water at 100°C is 2257 kJ/kg. Determine the enthalpy for apordato of iuod eeat capacity o
igomit [66]

Explanation:

The given data is as follows.

         T_{1} = 100^{o}C,       T_{2} = 10^{o}C

       \Delta H_{vap1} = 2257 kJ/kg,     \Delta H_{vap2} = ?

For water, C_{p} = 4.184 kJ/kg ^{o}C

Formula to calculate heat of vaporization is as follows.

  \Delta H_{vap1} - \Delta H_{vap2} = C_{p}(T_{1} - T_{2})

Hence, putting the values into the above formula as follows.

\Delta H_{vap1} - \Delta H_{vap2} = C_{p}(T_{1} - T_{2})

2257 kJ/kg - \Delta H_{vap2} = 4.184 kJ/kg ^{o}C (100 - 10)^{o}C

            \Delta H_{vap2} = 2257 kJ/kg - 376.56 kJ/kg

                                       = 1880.44 kJ/kg

Thus, we can conclude that enthalpy of liquid water at 10^{o}C is 1880.44 kJ/kg.

3 0
2 years ago
What are the two different types of ocean currents, and how are they formed?
suter [353]

Answer:

Explanation:

There are two main types of ocean currents: currents driven mainly by wind and currents mainly driven by density differences. Density depends on temperature and salinity of the water. Cold and salty water is dense and will sink. Warm and less salty water will float.

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Q: What property of propane does Rodriguez change using the burner? Support your answer with evidence from the text.
UNO [17]

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balloon is getting hit by stronger, colder winds from the west. He has plenty of propane fuel in

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Explanation:

7 0
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(b) what is the major product of the reaction at very low temperatures?
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