Answer:
The height of the jumping hill x = 189.3 m
Step-by-step explanation:
From Δ ABC
AB = x = height of the hill
∠A = 36° , ∠B = 90°
Thus ∠C = 180 - ∠A - ∠B
⇒ ∠C = 180 - 36 - 90
⇒ ∠C = 54°
x = 0.809 × 234
x = 189.3 m
This is the height of the jumping hill.
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390cm
1. find area of rectangle
1. 15cm x 20cm= 300 cm
2. find area of triangle
1. 1/2 (12 x 15)= 90cm
300+90