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3 years ago

Please help me, its due today!!!

Mathematics

1 answer:

Anastasy [175]3 years ago

3 0

Answer:

532$

Step-by-step explanation:

14% of 600 is 84 $

14% of 1200 is 168$

140 per day and there is 2 days so 140x2

add them all up and you get 532

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The table shows the number of hours the 25 college student spent studying for the final exam which histogram matches this data

Afina-wow [57]

Answer:

looks like B-cant really see the numbers

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

**Spam answers will not be tolerated**

Morgarella [4.7K]

Answer:

$f'(x)=-\frac{2}{x^\frac{3}{2}}$

Step-by-step explanation:

So we have the function:

$f(x)=\frac{4}{\sqrt x}$

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

$\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Therefore, our derivative would be:

$\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}$

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

$=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}$

Place the 4 in front:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}$

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})$

Distribute:

$=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}$

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

$=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }$

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

$= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}$

The numerator will use the difference of two squares. Thus:

$=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Simplify the numerator:

$=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Both the numerator and denominator have a h. Cancel them:

$=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Now, substitute 0 for h. So:

$=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})$

Simplify:

$=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})$

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

$=4( \frac{-1}{(x)(2\sqrt{x})})$

Multiply across:

$= \frac{-4}{(2x\sqrt{x})}$

Reduce. Change √x to x^(1/2). So:

$=-\frac{2}{x(x^{\frac{1}{2}})}$

Add the exponents:

$=-\frac{2}{x^\frac{3}{2}}$

And we're done!

$f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}$

5 0

3 years ago

Write down the two inequality equations that go with this graph below:

Simora [160]

The RED or Pink inequality equation is: y ≥ -3/2x - 5

The BLUE inequality equation is: y ≥ -1/2x - 3.

<h3>How to Write the Equation of an Inequality?</h3>

Once you know the slope (m) and y-intercept (b), in slope-intercept form y "inequality sign" mx + b, the inequality equation can be written.

Inequality equation for the Blue Line:

Find the slope (m) using the points (-2, -2) and (0, -3)

Slope (m) of the blue line = change in y/change in x = (-2 -(-3))/(-2 - 0)

Slope (m) of the blue line = 1/-2

Slope (m) of the red/pink line = -1/2

The y-intercept (b) for the red/pink line is: -3 (the value of y when x = 0).

We can use any possible inequality sign to state an inequality equation that go with the graph.

Substitute m = -1/2 and b = -3 into y ≥ mx + b:

y ≥ -1/2x - 3.

Inequality equation for the red/pink Line:

Find the slope (m) using the points (-2, -2) and (0, -5)

Slope (m) of the red/pink line = change in y/change in x = (-2 -(-5))/(-2 - 0)

Slope (m) of the red/pink line = 3/-2

Slope (m) of the red/pink line = -3/2

The y-intercept (b) for the red/pink line is: -5 (the value of y when x = 0).

Substitute m = -3/2 and b = -5 into y ≥ mx + b:

y ≥ -3/2x - 5

In conclusion, we have:

The RED or Pink inequality equation is: y ≥ -3/2x - 5

The BLUE inequality equation is: y ≥ -1/2x - 3.

Learn more about the inequality equation on:

brainly.com/question/11234618

#SPJ1

6 0

2 years ago

Simplifying by adding, subtracting, multiplying, or dividing: (2/3)-(2/5)

Volgvan

The answer is 4/15 or .26 with the 6 repeating forever.
Explanation: Least common multiple of 3 and 5 is 15. 2*5=10, 2*3=6. 10/15-6/15=4/15.

8 0

3 years ago

Help me on this please

Butoxors [25]

Answer:

y=35x+50

35*8=280

280+50=330

yes there will be 10 dollars left

I hope this is good enough:

8 0

3 years ago