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AVprozaik [17]
3 years ago
15

How do i solve 4m^2+3m-1=0 using the quadratic formula

Mathematics
1 answer:
elixir [45]3 years ago
8 0
Quadratic formulat is used when a^2+bx+c=0 x= \frac{-b+/- \sqrt{b^{2}-4ac}   }{2a} 4m^2+3m-1=0 a=4 b=3 c=-1 input x= \frac{-3+/- \sqrt{3^{2}-4(4)(-1)}   }{2(4)} x= \frac{-3+/- \sqrt{9+16}   }{8} x= \frac{-3+/- \sqrt{25}   }{8} x= \frac{-3+/-5  }{8} x= \frac{-8}{8} or \frac{2}{8} x=-1 or 1/4
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5(5t + 1) = 25t-7<br> Can someone help me with this solution??
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