Question

How do i solve 4m^2+3m-1=0 using the quadratic formula

Answer 1

Quadratic formulat is used when a^2+bx+c=0 x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$ 4m^2+3m-1=0 a=4 b=3 c=-1 input x= $\frac{-3+/- \sqrt{3^{2}-4(4)(-1)} }{2(4)}$ x= $\frac{-3+/- \sqrt{9+16} }{8}$ x= $\frac{-3+/- \sqrt{25} }{8}$ x= $\frac{-3+/-5 }{8}$ x= $\frac{-8}{8}$ or $\frac{2}{8}$ x=-1 or 1/4