Answer:
You plot the points on the coordinates of [3, 0], [-1, 0], [-3, 0].
Step-by-step explanation:
You set the whole thing equal to zero, and when evaluated correctly, you come up with the above answer.
I am joyous to assist you anytime.
The general equation of a hyperbola with a horizontal transverse axis is defined as:
x²/a² - y²/b² = 1
Solving for b², we use the formula: a² + b² = c²
b² = 12² - 9² = 63
Equation of our hyperbola will be:
x²/81 - y²/63 = 1
I think that (1/4)x+8 would be your algebraic expression.
