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padilas [110]
3 years ago
13

12/60 in lowest terms

Mathematics
1 answer:
Luda [366]3 years ago
8 0
Fractions can be simplified by making sure that the numerator and the denominator cannot be divided by any number.

The given 12/60 is very obvious that it is divisible by 2.
After dividing by 2, you will get 6/30.
It seems it is not in simplest form. It is divisible by 3.
Dividing the numerator and denominator by 3 then you will get 
2/15.

So the lowest term is 2/15.
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Biologists use a formula to estimate the mass of a mammal's brain.
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Answer:

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3 years ago
Write an equation of the line that passes through , 2.5−3.2 and is perpendicular to the line defined by =5x−2y.
Nitella [24]

Answer:

y=-1/5x-2.5

Step-by-step explanation:

3 0
4 years ago
the volume of a prism is 48 cubic meters. the height is two and length is 3 what is its width? delia chose a as the correct answ
sammy [17]
The answer is 8.
3 times 2 times 8 equals 48.
6 0
3 years ago
Harper’s parents put $75 into her school lunch money account. Each meal she gets from school costs her $3.25. The school sends H
BaLLatris [955]
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Hope this helps :D
3 0
3 years ago
A random sample of 1000 people was taken. Four hundred fifty of the people in the sample favored Candidate A. The 95% confidence
KatRina [158]

Answer:

The 95% confidence interval would be given (0.419;0.481).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

X=450 represent the people in the sample favored Candidate A

\hat p=\frac{450}{1000}=0.45 estimated proportion of people in the sample favored Candidate A  

\alpha=0.05 represent the significance level

Confidence =0.95 or 95%

p= population proportion of people in the sample favored Candidate A

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.5=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.45 - 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.419

0.45 + 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.481

And the 95% confidence interval would be given (0.419;0.481).

We are confident (95%) that about 41.9% to 48.1% of the people are favored Candidate A.  

3 0
3 years ago
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