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Taya2010 [7]
3 years ago
11

Compute the standard deviation for the set of data. 2, 4, 6, 8, 10

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0
\sigma - standard deviation
m - mean
\sigma= \sqrt{ \frac{1}{n} \sum_{i=1}^{n} (x_i-m)^2} 
\\m= \frac{2+4+6+8+10}{5}= \frac{30}{5} =6 \\ \\ \sigma= \sqrt{ \frac{1}{5} \sum_{i=1}^{5} (x_i-6)^2} 
\\= \sqrt{ \frac{1}{5} [ (2-6)^2+(4-6)^2+(6-6)^2+(8-6)^2+(10-6)^2]} 
\\= \sqrt{ \frac{1}{5} [ 16+4+0+4+16]} 
\\= \sqrt{ \frac{1}{5} \times 40} 
\\= \sqrt{ \frac{1}{5} \times 40} 
\\=2\sqrt{2}

balu736 [363]3 years ago
4 0
6 is the correct anwser

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F(x)=2x^3+ax^2-37x-60<br><br> The binomial x-4 is a factor of f(x). Find the value of a.
jekas [21]

Given:

The function is

f(x)=2x^3+ax^2-37x-60

The binomial x-4 is a factor of f(x).

To find:

The value of a.

Solution:

If x-c is a factor of f(x), then f(c)=0.

It is given that, x-4 is a factor of f(x), then f(4)=0.

We have,

f(x)=2x^3+ax^2-37x-60

Substituting x=4, we get

f(4)=2(4)^3+a(4)^2-37(4)-60

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f(4)=128+16a-208

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Now,

f(4)=0

16a-80=0

16a=80

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2 years ago
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Answer:

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